Substring with Concatenation of All Words - LeetCode #30 with Python, JavaScript and Java

Let's solve LeetCode #30 Substring with Concatenation of All Words!

Check out our latest tutorial on "Substring with Concatenation of All Words"! In this video, we explore the Substring with Concatenation of All Words problem on LeetCode, providing insights and strategies to solve this challenging algorithmic puzzle. Join us as we dissect the problem statement, discuss efficient approaches, and walk through detailed implementations to find substrings that concatenate all given words. Whether you're a novice or seasoned coder, our tutorial offers valuable tips and techniques to tackle Substring with Concatenation of All Words effectively. Don't miss out on unraveling the intricacies of Substring with Concatenation of All Words!

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■ Timeline
0:00 Read the question of Substring with Concatenation of All Words
2:08 Explain a basic idea to solve Substring with Concatenation of All Words
12:50 Coding
18:40 Time Complexity & Space Complexity

■ Problem Link

■ Codes in the video
- Python

- JavaScript

- Java

■ Playlists

#leetcode #python #interview #java #javascript

[CodingNinjaExAmazon]

Here is a step-by-step algorithm for Concatenation of All Words:

Input: A list of words
Output: A list of concatenated words

1. Create an empty dictionary to store the frequency of each word in the input list.
2. Loop through each word in the input list and increment its frequency in the dictionary.
3. Create an empty list to store the concatenated words.
4. Loop through each word in the input list.
5. For each word, check if it can be formed by concatenating any combination of other words in the input list.
6. If it can be formed, append it to the list of concatenated words.
7. Return the list of concatenated words.

Here is the detailed explanation of each step:

1. Create an empty dictionary to store the frequency of each word in the input list:
- We create an empty dictionary to store the frequency of each word in the input list. We will use this dictionary later to check if a word can be formed by concatenating other words in the input list.

2. Loop through each word in the input list and increment its frequency in the dictionary:
- We loop through each word in the input list and increment its frequency in the dictionary.

3. Create an empty list to store the concatenated words:
- We create an empty list to store the concatenated words that we will find.

4. Loop through each word in the input list:
- We loop through each word in the input list to check if it can be formed by concatenating any combination of other words in the input list.

5. For each word, check if it can be formed by concatenating any combination of other words in the input list:
- For each word, we check if it can be formed by concatenating any combination of other words in the input list.
- We do this by breaking down the word into all possible pairs of substrings and checking if each substring is present in the dictionary.
- If all substrings are present in the dictionary, then we know that the word can be formed by concatenating other words in the input list.

6. If it can be formed, append it to the list of concatenated words:
- If the word can be formed by concatenating other words in the input list, we append it to the list of concatenated words.

7. Return the list of concatenated words:
- Finally, we return the list of concatenated words that we have found.

[stevecharles]

Hi uper, when I submitted your code on the leetcode, it was stuck at the #179 test case with "Time Limit Exceeded", which is a test case with hundreds of "a" in words.

[schrodingerskatt]

The volume is very low, i can hardly hear anything !