The average of 41 consecutive odd numbers is 49. What is the ............? (#SSCCGL Maths Questions)

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Q83. The average of 41 consecutive odd numbers is 49. What is the largest number.
41 क्रमागत विषम संख्याओं का औसत 49 है सबसे बड़ी संख्या क्या है?
(a) 89 (b) 91
(c) 93 (d) 95
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SSC CGL TIER 2 2017
Exam Date: 17th February 2018
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Комментарии
Автор

41 consecutive number means middle number ke aage 20 number aur piche bhi 20 number.
And, haar 2 consecutive odd numbers ki difference 2.
Now, to find the largest number, 49 se 20 Ghar aage jaana hoga. Aur har ghar ki gap hain 2. So, 20x2= 40 ghar aage jana hain. 49+ (20×2) = 89 is the largest number.
Similarly, smallest number nikalne ke liye, 49 se 20 ghar piche jana hoga, so 49-(20x2) = 9 is the smallest number

Wolverine
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Aap bahut short video banate hai sir aise hi short Tarika aur padhaie taki ham acche se math Sikh sake

RahulKumar-vviv
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21st no. = 49
41st i.e., last odd number = 49+40 = 89

RohitPal-cweg
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Awesome concept sir jeeee aur video banaiye sir please🙏🙏

Masti.time
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The average of 5 consecutive numbers is, X,.if the last two consecutive numbers from the higher end are excluded.the everage will be?

turtanhoro
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Taat ur way of teaching is not good..🤣🤣🤣

hamala