What Is The Area?

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This is adapted from a problem given to 14-16 year old students. Watch the video to learn how to solve it!

Source (in Spanish)

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That line can't be 18. This question is incorrect on purpose for certain.

sporksto
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Pain is realizing you spent a half hour applying quadratics and geometry to a problem that is geometrically impossible.

OptimusPhillip
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You can just look at the diagram, and tell that those are impossible lengths.

andyiswonderful
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The line were the 10 is, is the longest possible line perpendicular to the large circle to the smallest one, therefore the lengths are impossible.

TatanAgustin
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The first thing I thought of when I saw the thumbnail:
That can't be right

alfewenxiao
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The most important issue in circles.
[ KEY POINT 1 ] Radius
[ KEY POINT 2 ] Pythagorean theorem
[ KEY POINT 3 ] Similarity
Remember!!!

mathmelody
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Well, I thought that the labelled lengths were screwy immediately, so I didn’t know what was going on

markphc
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For a change, I saw the "trick" part of the problem almost instantly. The way the original problem is set up, the distance on the right side of the two circles must be greater than the distance above (or below) the circles. As given, the construction is impossible. But you could make the construction possible again by setting the TOTAL distance of the above and below portions to equal 18. That would make each portion 9, which is less than 10, and the problem would be solveable.

oldguydoesstuff
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Would’ve been nice to see you derive, or at least show, the allowable values of a and b. I found them to be a < b < 2a

jackhiggins
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Woww...
The question you first solved is even not solved by graduate and post graduate students..The way these questions solve we could not even imagine
Because we dont see these type of questions before ..
Thanks for providing us such knowledge without any expense....

studies
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Give me a break, it should take exactly 1 second to know the question is wrong

et
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Getting recommended a Mind Your Decisions video from last year where Presh still used the term "Pythagorean Theorem" is a blessing.

advaitpetiwale
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You should've used *intersecting chords theorem.* It would be easier.

iamyoda
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This is the actual method to prove that the question is wrong.. thanks dear Paresh..sir..

kcpal
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Well another thing that came to mind directly when I saw you first problem was that
When circles are arranged like this .. the distance shall be maximum between the two circles at the horizontal gap line you have placed on the right size of the diagram between the two circles. .. so from starting it self I was skeptical to have a number 10 there and 18 on the vertical gap lines
Good one 😊👍👍

cakatikaggarwal
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I think you can you solve the problem using another method, which may be even simpler. A circle geometric theorem states that the product of intercepting chords are equal. Therefore if we denote R as the larger radius, R(R-18)= (R-10)^2. R^2-18R=R^2-20R+100. 2R=100, R=50.

antonsmirnov
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No one:
Mindyourdecisions: a middle schooler could solve this in under a minute! can YOU solve this problem?

onthespotstem
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Yeah i was skeptical in the beging but any way applied the formula

surajsapkal
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My first though was this can't be possible. Unless the two vertical distances sum to 18 and are actually 9 each. Just look at the drawing, the horizontal distance of 10 must be the max. Proving that would make for an interesting problem, but that is not what was asked.

arikwolf
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My method is dffferent.
• Perpendicular chord theorem leading to the value of the bigger radius
• then substituting the value to find diameter of the smaller circle in turn finding the value of smaller radius.
• finding area.

sadaa_aabhaari