Solving Publicis Sapient Python Data Engineer Interview Question | Second Round Interview |

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[mohdtoufique]

Hi Sagar, Thanks for the content..My approach
for a, b in enumerate (input):
output_list=[]
for c, d in enumerate(input):
if b<d and c>a:
output_list.append(d)
print(b, len(output_list), output_list)

[vikrantyadav]

for i in range(len(a)):
res=[]
count=0
for j in range(i+1, len(a)):
if a[j]>a[i]:
count+=1
res.append(a[j])
print(a[i], count, res)

[starmscloud]

Hello Sagar,
My Approach of doing this :


inputList:list = [99, 28, 12, 55, 13, 15, 76, 99]
for idx1, num1 in enumerate(inputList):
filteredList:list = [num2 for idx2, num2 in enumerate(inputList) if num2 > num1 and idx2 > idx1]
print(num1, len(filteredList), filteredList)

Output :


99 0 []
28 3 [55, 76, 99]
12 5 [55, 13, 15, 76, 99]
55 2 [76, 99]
13 3 [15, 76, 99]
15 2 [76, 99]
76 1 [99]
99 0 []

[kenpachi-zaraki]

Bhai umyea b batana tha ki count ko fir loop k under kyu liya print ko fir loop k under kyu liya toda explainaion or acha ho skta tha

[DataCoholic]

Take this optimised code guys:

input = [99, 28, 12, 55, 13, 15, 76, 99]
inputSet= set(input)
inputList=list(inputSet)
inputList.sort()

for item in inputList:
length=len(inputList)

print(item, length-(item_index+1), inputList[inputList.index(item)+1:])

[rallabandivijayvijay]

For index, value in enumerate(a):
X=[ j for i, j in enumerate(a) if j>value and i>index]
Print(value, len(x), x)

[tapaspal]

a=[99, 28, 12, 55, 13, 15, 76, 99]
d={}
temp=sorted(set(a))
print(temp)
for i in a:
for j in range(0, len(temp)):
if i==temp[j]:
d[i]=j
else:
pass
print(d)

[javeedmohammedabdul]

my approach
d=[99, 28, 12, 55, 13, 15, 76, 99]
for i in range(len(d)):
a=d[i]
b=[]
for j in range(i+1, len(d)):
if d[j]>a:
b.append(d[j])
print(f"{a} {len(b)} {b}")