D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13

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Exercise 6.3 Question 13 Class 10
or
Question 13 class 10 Exercise 6.3
D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC. Show that CA^2 = CB.CD.

HINT of Q13 of exercise 6.3 class 10
AA similarity criterion
If two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar

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INTRODUCTION
1.Two figures are said to be congruent, if they have the same shape and the same size.
2.Two figures having the same shape (and not necessarily the same size) are called similar figures.
3.All congruent figures are similar but the similar figures need not be congruent.
4.Two polygons of the same number of sides are similar, if (i) their corresponding angles are equal and (ii) their corresponding sides are in the same ratio (or proportion)

Note📝
The above question is taken from NCERT class 10 chapter Triangles Exercise 6.3 Question 13.

Practice :
Sides AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of Δ PQR . Show that Δ ABC ~ Δ PQR.

Revise✍🏻:
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Trigonometry

Quadratic Equation

Polynomials

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