Magic Geometry Construction | CMI Entrance 2022 B1 Problem, Idea and Solution| Math Olympiad

preview_player
Показать описание
Рекомендации по теме
Комментарии
Автор

HI, can't we directly use Menalaus Theorem? Beautiful construction, by the way. Thanks!

pramodk
Автор

By menelau's theorem in triangle XYZ using transversal RPQ, ZQ/YQ*YR/XR*XP/PZ =1,
So, k*XP/XR*(XY+XR) /(PW+WZ) =1,
k*XP/XR*(XY+XR)/(XP+XY)k=1,
XP(XY+XR)= XR(XY +XP),
XY(XP-XR) =0,
XP=XR, as XY can not be 0,
Is my solution correct? I did it in this way

swastikadey
Автор

Beautiful explanation sir ❤️❤️❤️❤️❤️❤️❤️❤️

asifhossain
Автор

I always wonder in geometry, how someone can be as able to do such perfect constructions... Maybe lots of practice. And it's what is most important in geometry problems.
I tried it very hard in cmi x'm, do some construction, Menelaus thm & all but nothing was satisfactory.

namantenguriya
Автор

I give cmi entrance exam I solved 29 questions in part a and 2 question in part b good pair and square cutting wala. What should I expect?

vineetjain
Автор

Around how many marks one should get in part B? I was also to solve only one question r^2+s^3 wala

sajaltuley
Автор

I want to admit online classes for my chaild who is in class eleven, and he is a math lovers, but can't enough study in agartala, plz help me to the right way to reach his goal.

subhranildeb
Автор

what could be the expected cutoff Part A and (Part A+Part B)

milindpatt