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0:05:46

If tanA = √2 - 1, then show that sinA.cosA = √2/4.

0:10:24

Prove that sinQ/(secQ + tanQ - 1) = 1 - cosQ/(cosecQ + cotQ - 1).

0:03:25

If (x-a)/(x-b) + (x-b)/(x-a) = a/b + b/a, then find x in terms of a and b.

0:06:46

Prove that 2/cos²Q - 1/cos⁴Q - 2/sin²Q + 1/sin⁴Q = cot⁴Q - tan⁴Q.

0:08:08

If sinx = cosx or sinx = -cosx, then find the value of x by using graph.

0:03:52

A quadrilateral PQRS circumscribe a circle. If PQ=12cm, QR=15cm & RS=14cm, then find length of SP.

0:02:34

In triangle ABC, DE || AB. If AB = a, DE = x, BE = b & EC = c. Then express x in terms of a, b & c.

0:01:00

Playing with Mercury

0:00:58

Trying to pick the mercury in a box.

0:03:37

Extracting mercury from a broken clinical thermometer and playing with mercury.

0:02:43

In ∆PQR right angled at Q. A point S is taken on side PR such that PS=SR & QR=QS. Find angle QRS.

0:03:31

Prove that sin^2A - sin^2B = sin(A+B)sin(A-B).

0:04:27

Proof of formula of cot3x = (3cotx - cot³x)/(1 - 3cot²x)

0:04:34

Proof of formula of tan3x = (3tanx - tan³x)/(1 - 3tan²x)

0:03:22

Proof of cos3x = 4cos³x - 3cosx

0:03:34

Proof of sin3x = 3sinx - 4sin³x

0:04:03

Proof of cosec2x = cosec^2x/(2√cosec^2x-1) = (1+cot^2x)/2cotx. | formula of cosec2x |

0:02:42

Proof of sec2x = sec²x/(2-sec²x) or sec2x = (1+tan²x)/(1-tan²x) | formula of sec2x |

0:02:51

Proof of tan2x = 2tanx/(1-tan²x) and cot2x = (cot²x-1)/2cotx.

0:05:42

Prove that cos2x = cos^2x-sin^2x = 2cos^2x-1 = 1-2sin^2x = (1-tan^2x)/(1+tan^2x).

1:07:54

Class 10th math Revised NCERT Exercise 9.1 Full exercise solved. According to new syllabus 2023-2024

0:05:12

Class 10 NCERT Exercise 9.1 Q15. A straight highway leads to the foot of a tower. A man standing at

0:05:55

Class 10 NCERT Exercise 9.1 Q14. A 1.2 m tall girl spots a balloon moving with the wind in a ...

0:04:47

Class 10 NCERT Exercise 9.1 Q13. As observed from the top of a 75 m high lighthouse from the sea