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lim x tends to 0 (1-cosmx/1-cosnx)=m^2/n^2

Lim x tends to 0 (e^ax-1/bx)=a/b

Lim n tends to (x^2+ax+c/x^2+bx+d)^(pa+q)=e^(a-b)p

Lim x tends to infinity (x^2+ax+c/x^2+bx+d)^x=e^(a-b)

Limit n tends to infinity:(1^p+2^p+...+n^p)/n^(p+1)=1/p+1. #jeeiitmaths

Limits:Lim x--0. sinax/sinbx=a/b. #iitjee

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