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0:03:27
If f(x)=2x^4−13x^2+ax+b is divisible by x^2−3x+2, then (a,b)=
0:00:53
Active mass of 0.64 SO2 in 10 lt vessel #iit prep solutions #shorts#study shorts
0:00:39
The mass of carbondioxide obtained when 2g of pure limestone is calcined is
0:00:42
The weight of a pure sample of KCIO, to be decomposed in order to get 1.92g of O, is
0:00:39
The weight of a pure sample of KCIO3, to be decomposed in order to get 1.92g of O, is
0:01:15
The mass of carbondioxide obtained when 2g of pure limestone is calcined is
0:00:46
1.38g of silver carbonate on strong ignition leaves a residue weighing4) 284g
0:00:36
1.38g of silver carbonate on strong ignition leaves a residue weighing4) 284g
0:00:45
The number of moles of C*O_{2} produced when 5 moles of HCl react with excess of CaCO 3 is
0:00:39
The number of moles of C*O_{2} produced when 5 moles of HCl react with excess of CaCO 3 is
0:00:40
✔ 3g of Mg reacts with excess of an acid. The amount of hydrogen produced would be
0:00:34
✔ 3g of Mg reacts with excess of an acid. The amount of hydrogen produced would be
0:01:24
10g of Caco3 is decomposed to X,Cao.X is passed into aqu Sol contain 1mole of NaHCO3.No.of moles of.
0:01:01
10g of Caco3 is decomposed to X,Cao.X is passed into aqu Sol contain 1mole of NaHCO3.No.of moles of.
0:00:48
1mole of F is reacted with 2mole of KOH.the products formed are KF,H2O,O2.molar ratio of products
0:01:00
1mole of F is reacted with 2mole of KOH.the products formed are KF,H2O,O2.molar ratio of products
0:00:57
C6H6 burns in O2 acc.to equation 2C6H6+15O2gives12CO2+6H2O.How many L of O2 for combustion of39g liq
0:00:55
C6H6 burns in O2 acc.to equation 2C6H6+15O2gives12CO2+6H2O.How many L of O2 for combustion of39g liq
0:01:18
The amount of Mg in gms,to dissolved in dilute H2SO4to H2which is just sufficient 160g of fe2o3 is
0:01:29
The amount of Mg in gms,be dissolve in dilute H2SO4toH2which is just sufficient reduce 160g fe2o3 is
0:00:58
60g of a compound on analysis gave C = 24g H = 4g and O = 32g Its empirical formula is
0:00:56
The empiricial formula of a compound is CH2O Its M.W is 120.The molecular formula of the compound is
0:01:15
60g of a compound on analysis gave C = 24g H = 4g and O = 32g Its empirical formula is
0:00:45
The empiricial formula of a compound is CH2O Its M.W is 120.The molecular formula of the compound is
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