The resultant of ๐‘ทย โƒ— and ๐‘ธย โƒ— is perpendicular to ๐‘ทย โƒ— . What is the angle between ๐‘ทย โƒ— and ๐‘ธย โƒ— :

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ะŸะพะบะฐะทะฐั‚ัŒ ะพะฟะธัะฐะฝะธะต
The resultant of ๐‘ทย โƒ— and ๐‘ธย โƒ— is perpendicular to ๐‘ทย โƒ— . What is the angle between ๐‘ทย โƒ— and ๐‘ธย โƒ— :
(A) ใ€–๐œ๐จ๐ฌใ€—^(โˆ’๐Ÿ)โก(๐‘ท/๐‘ธ) (B) ใ€–๐’„๐’๐’”ใ€—^(โˆ’๐Ÿ)โก((โˆ’๐‘ท)/๐‘ธ)
(C) ใ€–๐ฌ๐ข๐งใ€—^(โˆ’๐Ÿ)โก(๐‘ท/๐‘ธ) (D) ใ€–๐’”๐’Š๐’ใ€—^(โˆ’๐Ÿ)โก((โˆ’๐‘ท)/๐‘ธ)
Answer:
(B) ใ€–๐’„๐’๐’”ใ€—^(โˆ’๐Ÿ)โก((โˆ’๐‘ท)/๐‘ธ)
ะ ะตะบะพะผะตะฝะดะฐั†ะธะธ ะฟะพ ั‚ะตะผะต
ะšะพะผะผะตะฝั‚ะฐั€ะธะธ
ะะฒั‚ะพั€

Wow thanks for the sharing of questions๐Ÿ™‹๐Ÿ™‹

farhadshah