Mechanical Engineering: Ch 12: Moment of Inertia (49 of 97) Semi-Circle @ Center of Mass

preview_player
Показать описание

In this video I will find the moment of inertia (and second moment of area) I(C.M.)=? rotating around the C.M. parallel to the x-axis, of a semi-circle.

Next video in this series can be seen at:
  1. Michel van Biezen
  2. ilectureonline
  3. ilectureonline.com
  4. Mike
  5. Mike van Biezen
  6. van Biezen
Рекомендации по теме
Mechanical Engineering: Ch 0:04:29

Mechanical Engineering: Ch 12: Moment of Inertia (1 of 97) General Overview: 1/4

Mechanical Engineering: Ch 0:04:10

Mechanical Engineering: Ch 12: Moment of Inertia (5 of 97) What is 'First Moment of Area'?

Mechanical Engineering: Ch 0:02:35

Mechanical Engineering: Ch 12: Moment of Inertia (2 of 97) General Overview: 2/4

Mechanical Engineering: Ch 0:03:48

Mechanical Engineering: Ch 12: Moment of Inertia (8 of 97) Basic Shapes & Their Moment of Inerti...

Mechanical Engineering: Ch 0:01:59

Mechanical Engineering: Ch 12: Moment of Inertia (3 of 97) General Overview: 3/4

Mechanical Engineering: Ch 0:06:42

Mechanical Engineering: Ch 12: Moment of Inertia (48 of 97) Semi-Circle

Mechanical Engineering: Ch 0:02:53

Mechanical Engineering: Ch 12: Moment of Inertia (38 of 97) = 2nd Moment of Area: Rectangle 2

Mechanical Engineering: Ch 0:04:32

Mechanical Engineering: Ch 12: Moment of Inertia (10 of 97) First Moment of Area: Ex. 1

RRB JE 2024 1:45:05

RRB JE 2024 | Strength of Materials | RRB JE 2024 Mechanical Engineering Classes by Rahul Sir

Mechanical Engineering: Ch 0:05:27

Mechanical Engineering: Ch 12: Moment of Inertia (32 of 97) Parallel Axis Theorem: Circle

Mechanical Engineering: Ch 0:01:39

Mechanical Engineering: Ch 12: Moment of Inertia (4 of 97) General Overview: 4/4

Mechanical Engineering: Ch 0:09:26

Mechanical Engineering: Ch 12: Moment of Inertia (47 of 97) Parallel Axis Theorem Revisited

Mechanical Engineering: Ch 0:03:05

Mechanical Engineering: Ch 12: Moment of Inertia (27 of 97) Moment of Inertia=? Triangle

Mechanical Engineering: Ch 0:04:25

Mechanical Engineering: Ch 12: Moment of Inertia (9 of 97) Summary of 1st & 2nd Moments

Mechanical Engineering: Ch 0:04:50

Mechanical Engineering: Ch 12: Moment of Inertia (33 of 97) What is the Radius of Gyration?

Mechanical Engineering: Ch 0:05:24

Mechanical Engineering: Ch 12: Moment of Inertia (24 of 97) 2nd Moment of Area Rel. to Origin: Ex. 4

Mechanical Engineering: Ch 0:12:12

Mechanical Engineering: Ch 12: Moment of Inertia (35 of 97) Radius of Gyration (Area): Ex 1

Mechanical Engineering: Ch 0:07:17

Mechanical Engineering: Ch 12: Moment of Inertia (31 of 97) Parallel Axis Theorem

Mechanical Engineering: Ch 0:02:56

Mechanical Engineering: Ch 12: Moment of Inertia (22 of 97) 2nd Moment of Area Rel. to Origin: Ex. 2

Mechanical Engineering: Ch 0:07:31

Mechanical Engineering: Ch 12: Moment of Inertia (18 of 97) Second Moment of Area Compared

Mechanical Engineering: Ch 0:05:12

Mechanical Engineering: Ch 12: Moment of Inertia (19 of 97) Second Moment of Area Relative to y-Axis

Mechanical Engineering: Ch 0:03:49

Mechanical Engineering: Ch 12: Moment of Inertia (13 of 97) Second Moment of Area: Ex. 2

Mechanical Engineering: Ch 0:02:46

Mechanical Engineering: Ch 12: Moment of Inertia (37 of 97) = 2nd Moment of Area: Rectangle 1

Mechanical Engineering: Ch 0:03:26

Mechanical Engineering: Ch 12: Moment of Inertia (7 of 97) What is 'Moment of Inertia'?

Комментарии
Автор

Sir, why you using minus sign instead of plus

tariqultoki
Автор

determine by direct integration the moment of inertia of a semicircular area with respect to their centroidal axis?

Sir is this question solved by you?

tawsifridoy
Автор

Note: Icm=A((r²/4)-(a6r²/9pi²). Forgot the last pass. But, great.

lohanexugoi
Автор

Please help me on the step how to calculate 'D' please sir

Realistic