Area of an Equilateral Triangle with Incircle of Radius 2

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From the center to the middle of the left side of the triangle we have 2 units, from the center to the point C we have CO, and from the point C to the middle of the left side of the triangle we have x units, this makes a new triangle, so let’s find x, and then 2x, and then we have the A of the equilateral triangle. tg30=2/x —> x=2V3 units. X=2x=4V3 units. A=(X^2).(V3)/4 —> A=(4.4.3.V3)/4 —> A=12V3 u^2.

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Sir when we find the length of AB, cant we use the formula root3 divide by 2 and multiplied by a^2 to find the area of equilateral triangle.

RachnaBhusal