⚡Electricity: 10 Most Important Questions🧐[Class 10 Term 2 Physics] CBSE Boards 2022 Preparation

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⚡Electricity: 10 Most Important Questions🧐[Class 10 Term 2 Physics] CBSE Boards 2022 Preparation | CBSE Class 10 Science | Ncert Solutions for Class 10 #Vedantu9and10Hindi. How many of you are very perfect in Electricity Chapter? if you are not perfect don't worry about it, Your Favorite Master Teacher Abhishek Sir will discuss the "10 Most Important Questions from Electricity for Term 2 Board Exam. These 10 Questions are really important and those can be expected in your Term 2 Board Exam 2022, So do follow the session to know about those "10 Most Important Questions from Electricity for Term 2". We hope that this session will boost your score in Term 2. Check out this video and share it with your friends if you like the video!!

📢 🔥 Find all Subject in CBSE Class 10 Full Chapter Playlist Links:👇

📌 Topics Covered In this Session:
✦ 10 Most Important Questions from Electricity
✦ Electricity Class 10 Important Questions
✦ Electricity Class 10 Important Questions 2022
✦ Electricity Class 10 Important Questions term 2
✦ Electricity Class 10 Important Questions with Answers
✦ Electricity Class 10 Important Questions Vedantu
✦ Electricity Class 10
✦ Electricity Class 10 pdf
✦ Electricity Class 10 Notes
✦ Electricity Class 10 Solutions
✦ Electricity Class 10 Ncert Solutions
✦ CBSE Class 10 Physics Chapter 12
✦ CBSE Class 10 Board Exam 2022

#ElectricityImportantQuestions #Physics #CBSEClass10Science #Term2 #StayHomeAndLearn #BoardExam2022 #OnlineClasses #MilkeMachateHain

#Vedantu #learnliveonline

I hope you guys enjoyed & Gained Knowledge from this video on "⚡Electricity: 10 Most Important Questions🧐. See you in the next surprising ⏭️ session

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Here,
Time will be 30*5 =150 Hours
In first situation;
Energy=Power*time
=400*150
=60000Wh
=60 KwH
In 2nd situation ;
Energy=power*time
=32*150
=4800WH
=4.8KwH
So, energy saved will be:
60-4.8 = 55.2 units

silent.silent
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Homework Answer : 55.2 units

Solution :-
Case I :-
Given,
Power of each bulb = 100W, V = 220V, Total bulbs = 4, Time = 5hr, 30days
E = P×T = 4×100 × 5×30 = 60 units
Case II :-
Given,
Power of each LED = 8W, V = 220, Time = 5hrs, 30days, Total LED's = 4
E' = P' × T = 8×4 × 5×30 = 4.8 units

E' - E = 60 - 4.8 = 55.2 units.

Session was Fantastic🔥
Favourite part - Whole session
Thank you.🙂

VM_
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H. W answer :- 55.2
Amazing session

preetiatrey
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H.w answer:)
55.2 units

Solution:- Bulbs =4, time=5hr and 30 days(bcoz month)
E=P*T
E=4*5*30*100
E=60 units
Case leds(replace bulbs)
Same time=5 hrs 30 days
E'=P*T
E'=8*5*30*4=4.8
E-E'= 60-4.8 = 55.2 units

Awesome session as always💜🙌🙌
tararaara⚡🌝

oyeunnie
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The session was lovely ❤❤ I watched this at 5am just for I feel sleepy and you always brings a smile on all the faces of student and The homework is 55.2 units ✔

ayushsahu
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Amazing sessions sir...🙂❤️
HOMEWORK ANSWER: 55.2 units
Loved the whole session....☺️❤️❤️

komalkanwarrajawat
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Hw answer 55.2
Amazing Session Sir ❤❤
Jaanu Sall izz Best ❤❤
Dev-srivastava, tejas ki anjali, akshat-rashvi, menti is martimony now😂

SohamLearns
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I'm a bit late but still
HW answer - 55.2 units.
Today's session was ineffably amazing.

thegeniusgamers
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Session was Amazing 😌

H.w. Answer 55.2 units ✌🏽

MayankYadav-zzyc
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Homework answer - 55.2 units
Favorite part- when you gave Thunder hi 5.
Sir, you are amazing teacher of physics.

brijbhusanmalviya
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Answer for the homework question is 55.2 units option A

maulikjoshi
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H.W.ANS. 55.2 units
Favourite Part - Whole session❤

aayushiagrawal
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H.w ans: option a
Sal mai bhi hu wo bhi zinda 😂😂..ek hi to banta hai 😂😂😂
Amazing session 🤩
Peace ✌️

Aqsa_
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Super duper session 🥰😃😃
Hw : 55.2 units

pragatiprajapati
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Omg sir !! 38:21 Your reaction!!! LOL😆

shrutitripathi
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Homework answer
Option a, 55.2
I could get it by finding difference between the energy consumed by bulbs and the energy consumed by led.

mastikipaathshalawithsatya
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Thank you for the awesome session sir, mera favourite part toh pura session tha, aap itna achha padhate ho
Hw ans : ans. 55.2 units
E of 4 bulbs= 4× 0.1kw × 5hrs × 30 days
= 60 kwh or 60 units
E of 4 LEDs = 4 × 0.008 kw × 5hrs ×30 days
= 4.8 kwh or 4.8 units
Units of Energy saved in 30 days= delta E
= 60 units - 4.8 units
= 55.2 units

yuvraj_gameofwarriors
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Who is here for your science board class(10)
Hope you all score 40/40☺💙

asha-zhff
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Amazing session sir....
*But pls increase the size of diagram and option* so that it is clearly visible...

hritikasingh
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Wasn't able to watch the entire sess due to internet issues! :( But at least came on lb! 🙈😂 Will watch the sess tomorrow... pakka wala promise sall! 🙈😁
58:28 aise kaise bhul jau sir??🙈😂🤣🤣 (Nd me izz very patli not moti)🤣🤣
Balle balle... Tararara... Peace✌️

Sumedha_IIITR