Graphing Sine and Cosine with Transformations

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Graph y = Asin(B(x-D))+C and y = Acos(B(x-d))+C
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Based on your first definitions, aren't we suppose to shift D to the right if D > 0. Since π/4 is greater than 0, why are we shifting the left???

luisdfernandez
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you just saved my math grade, thank you

sofzhuk
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Oh, but I must say this was a great video nonetheless. You were very clear and it definitely resolved some of my issues. Thanks for contributing! :)

YoungFlyAmbitious
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This helped me so much! Thank you for posting this.

kir
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thank you! :D you just saved me from an F on my pre-calc test. :D thanks a bunch!

xBorderSauce
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how did you know that -pi/4 plus pi equal 3pi/4?

Majuuub
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@ 1:38 he says the original sin graph goes from the intervals 0 to pi/ 2. That was an error. It actually goes from 0 to 2pi.

YoungFlyAmbitious
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Thank you soo much!! You really helped clear up alot of my question:)

numbaspazzet
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Why you make me take notes of this Mr. Parra

prexci
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Thank you for the amazing explanation!

akhilgajjala
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Thank you for commenting. I annotated where I misspoke. I apologize for that.

Mathispoweru
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why is that the first point starts at NEGATIVE  1/4 i thought the horizontal shift is a posiive 1/4 (+ 1/4) i understand why we would shift down 1 unit down but why would we need to go negative horizontally to start our

yabseraberhe