Solving Amazon's most recent Interview question Array.concat (JavaScript Custom Implementation Ep-2)

[saitejagatadi]

Amazing video Vasanth. Thank you for your superb explanation. You mastered the art of writing clean code..

[vinaysharma]

You explained things very well and it was an amzing explanation from your side, thanks for explaining so well the custom implementation of array.concat method.

[vishalarora]

Hi Sir, I just wanted to start by saying how much I enjoy your videos and appreciate the effort you put into creating them.
I had a doubt here in this video. It is written in documentation that this method does not change the existing arrays, but instead returns a new array but here in the myConcat function i guess you are modifying the original array. I think it would be helpful if you could check this and correct me if I am wrong here. Thank you for your time and consideration.

[Spider-tokf]

InputArray should be like this
let inputArray = [...this];
because original array cannot change. btw I learn [...array] from your interview videos, thanks.

[thirukumaran]

if I used arrow function in my prototype I get this = {}, not the actual array's value. what happens here bro??

[algorithmictoolbox]

This is quite Strange

Array.prototype.test = function() {
let args = arguments;
console.log(typeof args); // Output: "object"
console.log(args.length); // Output: Number of arguments passed to the function
}


arguments is an object but still has property length? Is it array-like object or something? Object Prototype does not have length property
Or As we are using it inside Array.prototype - Its giving us access to .length ? What are your views in this ?