Chapter 6 | Question 30 | H C Verma - Friction | Physics for JEE Advanced

A person (40kg) is managing to be at rest between two vertical walls by pressing 1 wall A by his hand and feet and the other wall B by his back. Assume that the friction coefficient between his body and the wall is 0.8 and that limiting friction acts at all the contacts.
(a) Show that the person pushes the 2 walls with equal force .
(b) Find the normal force exerted by either wall on the person .(g=10m/s^2)

Admissions open for #IITJEE and #NEET #OnlineClasses

Please join us through any channel mentioned below:

#Olympiad #IITJEE #KVPY
Admissions open for #IITJEE and #NEET #OnlineClasses #Pathfinder #PathfinderSolutions #PathfinderPhysics #PathfinderOlympiad #IITJEEPhysics #JEEMain #JEEMains #JEEAdvanced #JEE2021 #JEE2022 #JEE2020
#IITJEEPhysicsLectures
#JEE
#JEEMainsPreparation
#IITJEE
#JEEExam
#IITJEEMains
#JEEMainsExam
#IITPhysics
#JEEPhysics
#IITJEEPhysics
#JEEPreparation
#IITExam
#IITMains
#IITPreparation
#PhysicsJEEMains
#IITJEEPreparation
#JEEMainPhysics
#IITJEEExam
#IITLectures
#BestCoachingForIIT
#OnlineCoachingForIITJEE
#LearnLiveOnline
#OnlineJEECoaching
#OnlineClasses
#howtocrackJEE
#strategy
#NEET
#NEETpreparation
#Physics
#IIT

[adityakumarsahoo]

Best explanation. Thanks sir.
26.11.22🔥