How To Calculate The Maximum Height In A Freefall Kinematics Problem

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Check out this exciting video where we tackle a free-fall kinematics problem! In this episode, we throw a ball straight up with an initial velocity of 5 meters per second. The ball rises, reaches its peak, and then falls back down, where we catch it at the same height we threw it. Our goal is to calculate various aspects of the ball's motion, such as its maximum height and time in the air.

First, we establish the known values of the problem, including the initial velocity of 5 m/s and the acceleration due to gravity, which is -9.8 m/s². We also note that at the peak, the ball's velocity is zero. Using the equation VF² = VO² + 2AD, we can determine the maximum height or displacement, which turns out to be 1.28 meters.

Next, we move on to finding the time it takes to reach the maximum height. Using the equation VF = VO + AT, we find that it takes approximately 0.51 seconds.

Then, we investigate the ball's velocity when it is caught. Since we catch it at the same height we threw it, we can use the same set of givens as before. By applying the equation VF² = VO² + 2AD, we discover that the velocity just before catching is 5 m/s, but in the opposite direction.

Lastly, we explore the total time the ball spends in the air. By observing that the time to reach the maximum height is half of the total time, we calculate that the ball is in the air for approximately 1.02 seconds.

If you found this video helpful or have any questions, please leave a comment below. We appreciate your support and look forward to assisting you. Enjoy the video!

Uses principles of kinematics to solve the following freefall physics problem.

I throw a ball up with a velocity of 5 m/s.
a) What is the maximum height the ball will reach?
b) How long does it take to reach the maximum height?
c) How fast is it moving when I catch it?
d) How long is the ball in the air? (the hang time)

If you can, try to solve the problem before I do.

This is a newer version of a previous (more detailed) version taught in class.
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im here studying 2 minutes before the quiz lmfao

mizukisolos
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How'd you calculate the max height with initial velocity and angle as given

Ex. A ball is thrown at an angle of 30 degrees, with an initial velocity of 28 m/s.

chuggy-yy
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2:52, you calculate -5 squared divided by 2 (-9.8) and you get 1.28, but i got 122.5?

tctoad