In figure , E is a point on side CB produced of an isosceles triangle ABC |Q11 Exercise 6.3 class 10

Exercise 6.3 Question 11 Class 10
In figure, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD ⊥ BC and EF ⊥ AC, prove that Δ ABD ~ Δ ECF.

HINT of Q11 of exercise 6.3 class 10

Read it :
INTRODUCTION
1.Two figures are said to be congruent, if they have the same shape and the same size.
2.Two figures having the same shape (and not necessarily the same size) are called similar figures.
3.All congruent figures are similar but the similar figures need not be congruent.
4.Two polygons of the same number of sides are similar, if (i) their corresponding angles are equal and (ii) their corresponding sides are in the same ratio (or proportion)

Note📝
The above question is taken from NCERT class 10 chapter Triangles Exercise 6.3 Question 11.

Practice :
CD and GH are respectively the bisectors of ∠ ACB and ∠ EGF such that D and H lie on sides AB and FE of Δ ABC and Δ EFG respectively. If Δ ABC ~ Δ FEG, show that:
(i) CD/GH = AC/FG
(ii) Δ DCB ~ Δ HGE
(iii) Δ DCA ~ Δ HGF

Revise✍🏻:
Circles:

Real Numbers:

Polynomials

Quadratic Equation

Trigonometry

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