Continue Your Python Script Even When urllib.request Encounters HTTP Errors

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How to Ensure Your Python Script Continues Running Despite HTTP Errors

Understanding the Problem

The Key Line Causing Issues

In your original code, you have the following line:

[[See Video to Reveal this Text or Code Snippet]]

This line attempts to open the URL and print its status before you’ve even entered the try-except block designed to handle potential HTTP errors. As a result, when an error occurs, it leads to an unhandled exception that crashes the program.

Proposed Solution

To address this issue and ensure your script continues running despite encountering HTTP errors, we need to modify the way URLs are checked in our script. Let's go through the steps to implement this change.

Step 1: Remove the Faulty Line

The first step is to remove the line that directly calls urlopen outside of the try-except block. Instead, we will rely on the urlopen call contained within the try-except segment.

Step 2: Rewrite the URL Request Logic

Let's rewrite the relevant portion of your script using a try-except block effectively:

[[See Video to Reveal this Text or Code Snippet]]

Key Changes

Encapsulation in Try-Except: By wrapping our URL requests in the try-except block, we prevent any unhandled exceptions from terminating the script.

Logging Errors: We still log the errors for later reference, but now the script continues to process any subsequent URLs in the list.

Conclusion

With these changes, your Python script will now handle HTTP error codes gracefully, allowing it to continue executing without termination. This is particularly useful when working through long lists of URLs, ensuring you capture as much information as possible without manual intervention for each error encountered.

Now you can confidently run your URL probing script, knowing that it will keep working through inaccuracies in web requests. Happy coding!