HashMap or Dictionary in python | PART - 22 | DSA in python in telugu | Engineering Animuthyam

Free python dsa course in Telugu | Part - q | Engineering Animuthyam

Free python dsa course in Telugu

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#coding #telugu #job #python #telugumemes #trendingreels #btech #college #java #javacoding #iit #pythontutorialtelugu
#nit #jee #eamcet #dsa

[anudeepkumardekkapati]

li=[2, 4, 2, 4, 2, 3, 2, 2]
li1=list(set(li))
print(li1)
n=len(li)
count=0
for i in range(len(li1)):
count=0
for j in range(0, n):
if li1[i] == li[j]:
count=count+1

print(li1[i], count)

[ananthsaigudla]

dic={}
list=[1, 2, 1, 2, 1, 1, 12, 2]
for i in range(len(list)):
if list[i] not in dic:
dic[list[i]]=1
else:
dic[list[i]]+=1
print(dic)

[phonegaming]

li=[1, 2, 3, 4, 5, 5, 5, 5, 5, 55]
dici={}
for i in range(len(li)):
dici[li[i]]=li.count(li[i])
print(dici)

[kapurocks]

Dictionary
Dictionaries are used to store data values in key:value pairs.

A dictionary is a collection which is ordered*, changeable and do not allow duplicates.

As of Python version 3.7, dictionaries are ordered. In Python 3.6 and earlier, dictionaries are unordered.

Dictionaries are written with curly brackets, and have keys and values:

ExampleGet your own Python Server
Create and print a dictionary:

thisdict = {
"brand": "Ford",
"model": "Mustang",
"year": 1964
}
print(thisdict)

[CharanKumar-xq]

a=[1, 5, 8, 0, 1, 8, 1, 5, 1]
dic={}
for i in range(len(a)):
count=0
for j in range (len(a)):
if a[i]==a[j]:
count=count+1
dic[a[i]]=count
Print(dic)

[Maheshkrishna-pb]

li = [1, 5, 8, 0, 1, 8, 1, 5, 1, 5, 8, 5]
l2 =[]
for i in range(len(li)):
count = 1
if li[i] in l2:
continue
for j in range(i+1, len(li)):
if li[i]== li[j]:
count +=1
l2.append(li[i])
print(li[i] , '=',count)


anna okasari chudu ee code to count no of times repeated a num in the list brutebforce vastundhi ni valla thank you anna regular ga classes upload chey

[idonthavejiminsjams]

arr=[1, 5, 8, 0, 1, 8, 1, 5, 1]
dici={}
for i in range(len(arr)):
for j in range(len(arr)):
if arr.count(i)==0:
break
if arr[i]==arr[j]:
dici[i]=arr.count(i)
print(dici)

[charankumarreddy]

li=[1, 5, 8, 0, 1, 8, 1, 5, 1]
n=len(li)
dici={}
for i in range(n):
val=li[i]
if val not in dici:
dici[val]=1
else:
temp=dici[val]
dici[val]=temp+1
print(dici)

[peddintiganesh-gu]

chala slow ga velthunnamm compare to java so it is better do some long videos bro...
Python is easy compare to java so you can give more concepts and problem in single video and provide @DSA sheet for preparation

[kandelarajavamshi]

li=[1, 5, 8, 0, 1, 8, 1, 5, 1]
raj={}
for i in range(len(li)):
if li[i] not in raj:
raj[li[i]]=1
else:
raj[li[i]]+=1
print(raj)

[sagantyc.sharonlee]

li=[1, 5, 8, 0, 1, 8, 1, 5, 1]
dici={}
for i in range(len(li)):
count=1
for j in range(i+1, len(li)):
if li[i]==li[j]:
count+=1
if li[i] not in dici:
dici[li[i]] = count

print(dici)

[mrtejadithya]

j=dict()
def dicty(arr):
for i in arr:
if i in j:
j[i]+=1
else:
j[i]=1
return j
print(dicty([1, 5, 8, 0, 1, 8, 1, 5, 1]))

[SindhujaReddy-gwfo]

l1=[1, 5, 8, 0, 1, 8, 1, 5, 1]
dic={}
dic[1]=0
dic[0]=0
dic[5]=0
dic[8]=0
count=0
for i in l1:
if i in dic:
dic[i]=dic[i]+1
print(dic)

[mahesh]

Anna notes upload cheyyava
And classes kuda regular ga upload cheyavaa final year students ki chala help

[karthikphotoeditz]

Explanation chala bagundi macha full video chusa
And china doubt machaa ee course lo oops concept kuda explain chestava please reply machaa 😢😢❤❤❤❤

[BATTULARANGAIAH-CSE]

arr=[1, 5, 8, 0, 1, 5, 1]
n=len(arr)
dict={}
dict[1]=1
dict[5]=1
dict[8]=1
dict[0]=1
dict[1]=dict[1]+1
dict[1]=dict[1]+1
dict[8]=dict[8]+1
dict[5]=dict[5]+1
dict[1]=dict[1]+1
print(dict)

[charan_cherry]

dici={}
arr = [1, 5, 8, 0, 1, 8, 1, 5, 1]
for i in arr:
if i not in dici:
dici[i]=1
elif i in dici:
dici[i]+=1
for i in dici:
print(f'{i}->{dici[i]}')

[Ahamed]

# l=[2, 3, 4, 2, 1, 1, 1, 2, 4]
# n=len(l)
# dict={}
# count=0
# for i in range(n):
# if l[i] not in dict:
# dict[l[i]]=1
# else:
# dict[l[i]]+=1
# print(dict)

OR

from collections import Counter
l=[2, 1, 2, 1, 3, 4, 1, 3, 3, 4]
print(Counter(l))

[SnehaArvapally]

li=[1, 5, 8, 0, 1, 8, 1, 5, 1]
dici={}
for i in range(len(li)):
dici[li[i]]=0
for i in range(len(li)):
if li[i] in dici:
dici[li[i]]=dici[li[i]]+1
print(dici)

[BALIGARISURENDRAREDDY-CSEU]

list1 = [1, 5, 8, 0, 1, 8, 1, 5, 1]
dici = {}
for i in range(len(list1)):
if list1[i] not in dici:
dici[list1[i]] = 1
else:
dici[list1[i]] = dici[list1[i]] + 1
print(dici)