Find The Inverse Of The Complex Number 1 + i

Find The Inverse Of The Complex Number 1 + i

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[quantum]

In general the number (a+bi)^(-1) is equal to a/(a^2+b^2) - bi/(a^2+b^2)

[syedrehanfida]

You're a great teacher. Thank you so much!

[bradryan]

I have looked up your credentials, and clearly you are a mathematics teacher. Therefore I am confused as to what you have presented here. The INVERSE of a relation has nothing to do with raising something to the power of minus one. For example, ( sin x ) ^-1 has nothing to do with sin ^-1 x. The first is raising the relation to the power of minus one, which is in fact reciprocating the relation, whereas the second has to do with reflecting in the line y = x and is the inverse of the original relation. In your example you have found the reciprocal of a complex number NOT its INVERSE. If I have misinterpreted something here, or if terminology is different for you, please explain.