11th PHYSICS | UNITS AND MEASUREMENT | DIMENSION | LECTURE 03 | PRADEEP GIRI SIR

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11th PHYSICS | UNITS AND MEASUREMENT | DIMENSION | LECTURE 03 | PRADEEP GIRI SIR
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Dimensions of Force
Force = m × a
= [L⁰M¹T⁰] × [L¹M⁰T-²]
= [L¹M¹T-²]
12:02 : HW 👆👆

Dimension of Pressure
Pressure = F / A
= [L¹M¹T-²] / [L²M⁰T⁰]
= [L¹M¹T-²]× [L-²M⁰T⁰]
= [ L-¹M¹T-²]

16:27 : HW👆

Dimensions of Area
Area = [L²M⁰T⁰]

THANK YOU SO MUCH SIR FOR YOUR SUPPORT AND TEACHING❤❤❤

PLEASE CHECK MY ANSWER 🙏🏻

rishabhbandhekar
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GT Systmm 😎🙌
Physics Becomes easier when Pradeep Sir starts teaching 😊❤
Thank you sir ji

shubhamchauhan
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Dimensions of force
Force=m×a

=[L⁰ M¹ T⁰]×[L¹M⁰T-²]
=[L¹M¹T-²
Dimensions of pressure
Pressure =F/A
=[L¹M¹T-²]/[L²M⁰T⁰]
=[L¹M¹T-²]×[L-²M⁰T⁰]
=[L-¹M¹T-²]
Dimensions of area
Area=[L²M⁰T⁰]

TheRadhana
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12:19 force dimension- [ M¹ L¹ T-² ]
P=F/A
P= [ M¹L¹T-² ] / [ M⁰L¹T⁰ ]²
P=[ M¹L¹T-² ] / [ M⁰L²T⁰ ]
P=[ M¹L-¹T-² ]

bhaiyajiireturns
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12:00 L1 M1 T-2
AREA'S unit = meter square
Pressure= L-1 M1 T-2

ansariarmash
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[L¹M¹T-²]\[L²M⁰T⁰] =[L-¹M¹T_²] dimension of pressure

GauravBorkar-is
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Force dimension : [ L1 M 1 T-2 ]
Area dimension: [ L2 M0 T0 ]
Pressure= [ L-1 M1 T-2 ]

its_riya
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Thankqq soo much sir for your efforts...!

sanskrutibadkas
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Thanks sir aapka lecture mujhe acha laga

amitvish
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Thank you sir for making videos for us

educationlearner
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12:03 F = [L1 M1 T-2]


P=F/A


[L1 M1 T-2]

[L2 M0 T0]

=[L-1 M1 T-2]

anshmishra
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Dimensions of force =
F= m×a
=[L⁰M¹T⁰]×[L¹M⁰T‐²]
=[L¹M¹T-²]

DreamSSC-we
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Isleye main sib AAP ka dekhta hu giri tutorials

amitvish
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P = F/A

A = [ L M T ]
AS A = m²
therefore, . A = [.L² M⁰ T⁰ ]


As, . P = F/A
= [ L¹ M¹ T-² ] /. [. L² M⁰ T⁰ ]
= [ L-¹. M¹. T-² ]


THANK YOU SO MUCH SIR ❤❤❤❤

aartipitty
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Area = square [M²]
Pressure= L-1 M1 T-2

pranavdayanandlomate
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the answer for pressure is P=[M1L-1T-2] plz reply if correct

technoprash