Mechanical Engineering Thermodynamics - Lec 23, pt 4 of 4: Example - Ideal Vapor-Compression

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Problem source: Q10.14, Cengel and Boles, Thermodynamics, 3rd Edition
  1. Ron Hugo
  2. Thermodynamics (Field Of Study)
  3. Mechanical Engineering (Professional Field)
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Table A-12 is how you get h1, since in the problem it is stated that it is a Saturated Vapor, therefore you look at the table under 140 kPa and 800 kPa. By doing this you can find both Enthalpy and entropy. Correction, you do use the superheated tables but that is only for P2, where the line does show up outside of the saturated line. From there you interpolate to get h2 after assuming that S1=S2

chrisperez
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You use the superheated R-134a table at a pressure of 0.8 MPa.  Knowing that the value of entropy at state 1 is equal to entropy at state 2 (3:25 in the video), this provides you with the value of entropy (s_2) at 0.8 MPa.  You then interpolate for h_2 from the superheated table knowing s_2.

ronhugo
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the problem with my superheated R-134a table is my pressure at .8mpa is not there. i got  only pressure column for .6mpa and .10mpa  

hassannaser
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why my h1 is differt form yours? how did you get that?

Chess.Infinity
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hello sir ... i have trouble in finding h3 as the value in R-134a I used is way bigger than the value used in this video ... how to get 93.42 for h3... pls do help

neetishneetishwaran
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Hey Ron, love your videos on thermodynamics, is there anyway I can message you for some help with some exam type cycle questions?

axessoriiaxessorii
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Haha how did you get H2 you don't have visual explanation.

adriprz_
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i cannot find h2 can you sir explain ?

eslammohtady
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based on a P1 of 140 Kpa, and the fact that it is a sat. vapor why can you not find h1=approx 387 from the tables? All of your values for h and s are much lower than my tables even have?

calm