Find distance travelled based on constant acceleration

I discuss an exercise in which we are told that an auto accelerates from 5 km/hr to 80 km/hr in 9 seconds. Assuming a constant acceleration, we are asked to determine the distance traveled in meters in those 9 seconds. Since the information is given in both meters and km, as well as both seconds and minutes, unit conversion is required. After that, we use antidifferentiation (integration) to determine the velocity and position functions.

[alexandermarcelo]

Alexander Espinosa, MAC2311, M-R 2pm
"The rate of change is the slope...we can think of the x being the seconds and the y being the velocity"

[MyGamer]

Fathin Hossain
MAC2311, M-R 2pm
"I'm going to multiply in such a way that I can cancel out these dimensions and get the ones that I want."

[sermonsermon]

Sabrine Charles
MAC2311 M-R 2pm
finding the slope using x as inputs and y as output helps determine the rate of change as a numerical value which
is the accelaration

[paulchavez]

Paul Chavez
MAC2311 M-R 2pm


"that change on 9 seconds tell us the acceleration, and that rate of change is the slope"

[victoriasueropagan]

Victoria Suero
MAC2311 M-R 2:00 p.m.
".. we can convert 80 km/h in terms of meters and seconds and we can use the information they gave us about the nine seconds to accelerate from twenty five eighteenth's meters..."

[sermonsermon]

Sabrine Charles
Mac2311 M-R 2PM
"the rate of change is the slope"

[juantomasini]

MAC2311


"Focus on change the problem information to the same unit (m/sec)"

[Learn--Code]

Michael Samuels MAC2311, M-R 2pm
"The rate of change is the slope"

[Tautviss]

why you dont covert into meters per 1 second?

[sakalianamoto]

why did you used the intial velocity as a constant??

[taylathompson]

MAC2311, M-R 2pm

“We have two different time measurement units, seconds vs hours and meters vs kilometers”

Tayla Thompson