Python Interview Question asked in Amazon for Business Research Analyst

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[SumitKumar-vxfe]

def min_step(num):
count = 0
while(num!=0):
if(num%2==0):
num = num//2
count = count + 1
else:
num = num - 1
count = count + 1
return count

print(min_step(12))

O/p = 5

[hariprasath]

# steps required to reduce a number to 0

inp= int(input("Enter the number: "))
steps=0
val= inp
while (val!=0):
if (val % 2 !=0):
val = val - 1
val = val / 2
steps = steps + 1
elif( val %2 ==0):
val = val / 2
steps = steps + 1
if val <= 0 :
break
print(val, steps)

[sayantanganguly]

number = 1
number1 = number -1
print(number 1)

As simple as that

[hariprasath]

you are starting the range with 0, so the step size is going to be always -1 the actual step size taken.

[prajwalgs]

n=int(input())
for i in range(n):
if n%2==0:
n=n/2
elif n%2==1:
n=n-1

if n<=0:
break
print(i)
bro, i got this as output (i=4) it is the lowest reduced value, i got . it is right or wrong tell me