Functional Equation jee mains pyq #jeemains #jee #maths

Functional Equations in JEE Mains can be challenging, but not anymore! 💡 Dive into this video to tackle previous year questions like a pro! 📚 Get ahead in your preparation now! 💥

[yashyt]

Answer = 8

Solution :
4f(-24) + 3f(27) = 27²
4f(27) + 3f(-24) = (-24)²
Solving this
f(27) = 117/7
Similarly
4f(-22) + 3f(25) = 25²
4f(25) + 3f(-22) = (-22)²
Solving this
f(25) = 61/7
f(27) - f(25) = 56/7 = 8....
Thank you ❤❤❤

[LowCastImpulse]

Replacing (3-x) by x and solving the equations simultaneously gives
f(x)=[4(3-x)²-3x²]/7

[SpoidyRizz]

Answer is 8 you can also put x=3-x and substract to make equation in only fx.
These short videos are really helpful for revision sir thank you so much and please make such videos till jee mains ❤️❤️

[swetapadmamahapatra]

The answer is 8.
The relation is given to be :
4f(3-x) + 3f(x) =x²
Putting 27 in the equation, we get,
4f(-24) +3 f(27) = 729
Then again by putting -24, we get,
4f(27) + 3f(-24) = 576
Solving the simultaneous equations, we get:
f(27) = 117/7.
Now by putting 25 in the equation, we get,
4(-22) +3f(25) = 625.
Again by putting -22, we get
4(25) + 3f(-22) = 484
By solving we get
f(25) = 61/7
Now f(27)-f(25) = (117/7)-(61/7) = 56/7 =8.
Thank you sir😊

[Mayank-vjfw]

Thanks sir i might have stopped after second step ❤

[Mathslover]

Directly x ko 3-x kardo do equation solve answer 8

[mathssurvivor]

First we find
f(x)= (x² - 24x + 36) / 7
Then f(27) - f(25) = 8

[Jainam]

Sir jee 2026 ke liye live/long vdo mcq solve series st kroge ??❤

[ShubhamYadav-efpn]

Process a gaya bas calculation weird hai