951. Flip Equivalent Binary Trees | LeetCode 951 Explained in Java | Code Explanation & Dry Run

In this video, we solve the "Flip Equivalent Binary Trees" problem from LeetCode (Problem #951). This is a medium-level problem where we're given two binary trees and need to determine if they are "flip equivalent." A flip operation allows us to swap the left and right subtrees of any node.

We'll go step-by-step through the problem, explain the recursive approach in detail, and implement the solution in Java.

Key Concepts:
Binary Tree
Recursion
Flip Operation
What you'll learn:
How to handle recursive problems involving binary trees.
The logic behind checking equivalence with and without flipping subtrees.
Writing clean and efficient Java code for tree-based problems.
Problem Overview:
Given the roots of two binary trees, we need to check if they are flip equivalent, which means one tree can be transformed into the other by flipping some nodes' left and right children. Time Complexity:
O(N), where N is the total number of nodes in both trees, since each node is visited once.

Space Complexity:
O(H), where H is the height of the tree, due to the recursion stack.

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