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Ratio, Proportion, Indices and Logarithm | CA Foundation | Ex 1 A (20)
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All CA Foundation Exercises solved!
Course : ๐๐ ๐ ๐จ๐ฎ๐ง๐๐๐ญ๐ข๐จ๐ง May, 2022 examination onwards | Topic : ๐๐๐ญ๐ข๐จ, ๐๐ซ๐จ๐ฉ๐จ๐ซ๐ญ๐ข๐จ๐ง, ๐๐ง๐๐ข๐๐๐ฌ ๐๐ง๐ ๐๐จ๐ ๐๐ซ๐ข๐ญ๐ก๐ฆ
Exercise - ๐ (๐)
๐๐ฎ๐๐ฌ๐ญ๐ข๐จ๐ง ๐๐ฎ๐ฆ๐๐๐ซ : ๐๐ - If p : q is the sub-duplicate ratio of p - xยฒ : q - xยฒ then xยฒ is โฆ?
๐๐ฉ๐ญ๐ข๐จ๐ง (๐) : p / p + q
๐๐ฉ๐ญ๐ข๐จ๐ง (๐) : q / p + q
๐๐ฉ๐ญ๐ข๐จ๐ง (๐) : pq / p + q
๐๐ฉ๐ญ๐ข๐จ๐ง (๐) : None of these
#ca
#cafc
#maths
#module
๐๐จ๐ง๐๐๐ฉ๐ญ๐ฌ ๐จ๐ ๐๐๐ญ๐ข๐จ๐ฌ
โ๏ธ A ratio is a comparison of the sizes of two or more quantities of the same kind by division.
โ๏ธIf p and q are two quantities of the same kind, then the fraction p/q is called the ratio of p to q.
โ๏ธThe quantities p and q are called terms of the ratio.
โ๏ธThe first term p is called antecedent.
โ๏ธThe second term q is called consequent.
โ๏ธBoth the terms of a ratio can be multiplied or divided by the same non-zero number.
โ๏ธUsually a ratio is expressed in lowest terms.
โ๏ธThe order of the terms in a ratio is important.
โ๏ธRatio exists only between quantities of the same kind. Quantities to be compared must be in same units.
โ๏ธTo compare two ratios, convert them into equivalent like fractions.
๐๐ซ๐จ๐ฉ๐๐ซ๐ญ๐ข๐๐ฌ ๐จ๐ ๐๐๐ญ๐ข๐จ๐ฌ
โ๏ธA ratio a : b is said to be of greater inequality if a greater than b and of less inequality if a less than b.
โ๏ธThe ratio compounded of the two ratios a : b and c : d is ac : bd.
โ๏ธThe inverse ratio of a : b is b : a
โ๏ธThe duplicate ratio of a : b is aยฒ : bยฒ
โ๏ธThe triplicate ratio of a : b is aยณ : bยณ
โ๏ธThe sub-duplicate ratio of a : b is โa : โb
โ๏ธThe sub-triplicate ratio of a : b is ยณโa : ยณโb
โ๏ธIf the ratio of two similar quantities can be expressed as a ratio of two integers, the quantities are said to be commensurable, otherwise, they are said to be incommensurable.
โ๏ธContinued ratio is the relation or comparison between the magnitude of three or more quantities of the same kind.
๐๐ซ๐๐ง๐ฌ๐๐ซ๐ข๐ฉ๐ญ / ๐๐ฎ๐๐ญ๐ข๐ญ๐ฅ๐๐ฌ
We now discuss Question Number 20 from Exercise 1A. The question is... if p is to q is the sub-duplicate ratio of p minus xยฒ is to q minus xยฒ then xยฒ is...? So we have a ratio p minus xยฒ is to q minus xยฒ and the sub duplicate ratio of this ratio is p is to q. Now in order to obtain the sub duplicate ratio of this ratio we take the square root. So root of p minus xยฒ; that is root of antecedent and the root of consequent. It is root of q minus xยฒ and now we have obtained the sub duplicate ratio; but this sub duplicate ratio is given to be p is to q. So the sub duplicate of p minus xยฒ is to q minus xยฒ... that is root of p minus xยฒ is to root of q minus xยฒ is p is to q and we have to check which... the value for xยฒ. Which of these is value of xยฒ...? So let us simplify this and isolate x. So squaring both sides here the root gets eliminated. So we have p minus xยฒ upon q minus xยฒ and if we square the right hand side we have pยฒ upon qยฒ. Let's cross multiply; so we have qยฒ times p minus xยฒ which is equal to pยฒ times q minus xยฒ. We open up the brackets here. So we have pqยฒ minus qยฒxยฒ ...is equal to... now here... if you multiply; we have pยฒq minus pยฒxยฒ. Now we collect the xยฒ terms on one side. Let us transfer this over here. So we have a pยฒxยฒ minus qยฒxยฒ is equal to.. now on the right hand side we have pยฒq and this term we transfer it on the right. It becomes minus pqยฒ. Now taking xยฒ term common; so in brackets we have pยฒ minus qยฒ. Now here we could take pq as a common factor. So in brackets we have p minus q. So from here we obtain xยฒ as pq into p minus q divided by pยฒ minus qยฒ. But the denominator could be further factorized...so we have xยฒ is equal to pq into p minus q and the denominator could be split as p plus q into p minus q. Now p minus q gets cancelled. So we have xยฒ equal to pq upon p plus q. So we have obtained x square. Let's check with the options now. pq upon p plus q. No we have pq upon p minus q over here. So the correct answer is Option D: none of these.
๐๐๐จ๐ฎ๐ญ ๐๐๐ญ๐ก๐ฌ ๐๐ฅ๐๐ญ๐ญ๐๐ซ
๐๐ฆ๐ฉ๐จ๐ซ๐ญ๐๐ง๐ญ ๐๐ข๐ง๐ค๐ฌ
๐ ๐จ๐ซ ๐ฆ๐จ๐ซ๐ ๐ข๐ง๐๐จ๐ซ๐ฆ๐๐ญ๐ข๐จ๐ง
๐ฑ๐๐๐ ๐๐ on Facebook at @mathscart.
๐ญ๐๐๐๐๐ ๐๐ on Twitter at @maths_platter
๐ซ๐๐๐๐๐๐๐ ๐๐๐๐๐ on our telegram at @mathsplatter.
And remember, you can learn anything. For free. For everyone. Forever. #YouCanLearnAnything
Course : ๐๐ ๐ ๐จ๐ฎ๐ง๐๐๐ญ๐ข๐จ๐ง May, 2022 examination onwards | Topic : ๐๐๐ญ๐ข๐จ, ๐๐ซ๐จ๐ฉ๐จ๐ซ๐ญ๐ข๐จ๐ง, ๐๐ง๐๐ข๐๐๐ฌ ๐๐ง๐ ๐๐จ๐ ๐๐ซ๐ข๐ญ๐ก๐ฆ
Exercise - ๐ (๐)
๐๐ฎ๐๐ฌ๐ญ๐ข๐จ๐ง ๐๐ฎ๐ฆ๐๐๐ซ : ๐๐ - If p : q is the sub-duplicate ratio of p - xยฒ : q - xยฒ then xยฒ is โฆ?
๐๐ฉ๐ญ๐ข๐จ๐ง (๐) : p / p + q
๐๐ฉ๐ญ๐ข๐จ๐ง (๐) : q / p + q
๐๐ฉ๐ญ๐ข๐จ๐ง (๐) : pq / p + q
๐๐ฉ๐ญ๐ข๐จ๐ง (๐) : None of these
#ca
#cafc
#maths
#module
๐๐จ๐ง๐๐๐ฉ๐ญ๐ฌ ๐จ๐ ๐๐๐ญ๐ข๐จ๐ฌ
โ๏ธ A ratio is a comparison of the sizes of two or more quantities of the same kind by division.
โ๏ธIf p and q are two quantities of the same kind, then the fraction p/q is called the ratio of p to q.
โ๏ธThe quantities p and q are called terms of the ratio.
โ๏ธThe first term p is called antecedent.
โ๏ธThe second term q is called consequent.
โ๏ธBoth the terms of a ratio can be multiplied or divided by the same non-zero number.
โ๏ธUsually a ratio is expressed in lowest terms.
โ๏ธThe order of the terms in a ratio is important.
โ๏ธRatio exists only between quantities of the same kind. Quantities to be compared must be in same units.
โ๏ธTo compare two ratios, convert them into equivalent like fractions.
๐๐ซ๐จ๐ฉ๐๐ซ๐ญ๐ข๐๐ฌ ๐จ๐ ๐๐๐ญ๐ข๐จ๐ฌ
โ๏ธA ratio a : b is said to be of greater inequality if a greater than b and of less inequality if a less than b.
โ๏ธThe ratio compounded of the two ratios a : b and c : d is ac : bd.
โ๏ธThe inverse ratio of a : b is b : a
โ๏ธThe duplicate ratio of a : b is aยฒ : bยฒ
โ๏ธThe triplicate ratio of a : b is aยณ : bยณ
โ๏ธThe sub-duplicate ratio of a : b is โa : โb
โ๏ธThe sub-triplicate ratio of a : b is ยณโa : ยณโb
โ๏ธIf the ratio of two similar quantities can be expressed as a ratio of two integers, the quantities are said to be commensurable, otherwise, they are said to be incommensurable.
โ๏ธContinued ratio is the relation or comparison between the magnitude of three or more quantities of the same kind.
๐๐ซ๐๐ง๐ฌ๐๐ซ๐ข๐ฉ๐ญ / ๐๐ฎ๐๐ญ๐ข๐ญ๐ฅ๐๐ฌ
We now discuss Question Number 20 from Exercise 1A. The question is... if p is to q is the sub-duplicate ratio of p minus xยฒ is to q minus xยฒ then xยฒ is...? So we have a ratio p minus xยฒ is to q minus xยฒ and the sub duplicate ratio of this ratio is p is to q. Now in order to obtain the sub duplicate ratio of this ratio we take the square root. So root of p minus xยฒ; that is root of antecedent and the root of consequent. It is root of q minus xยฒ and now we have obtained the sub duplicate ratio; but this sub duplicate ratio is given to be p is to q. So the sub duplicate of p minus xยฒ is to q minus xยฒ... that is root of p minus xยฒ is to root of q minus xยฒ is p is to q and we have to check which... the value for xยฒ. Which of these is value of xยฒ...? So let us simplify this and isolate x. So squaring both sides here the root gets eliminated. So we have p minus xยฒ upon q minus xยฒ and if we square the right hand side we have pยฒ upon qยฒ. Let's cross multiply; so we have qยฒ times p minus xยฒ which is equal to pยฒ times q minus xยฒ. We open up the brackets here. So we have pqยฒ minus qยฒxยฒ ...is equal to... now here... if you multiply; we have pยฒq minus pยฒxยฒ. Now we collect the xยฒ terms on one side. Let us transfer this over here. So we have a pยฒxยฒ minus qยฒxยฒ is equal to.. now on the right hand side we have pยฒq and this term we transfer it on the right. It becomes minus pqยฒ. Now taking xยฒ term common; so in brackets we have pยฒ minus qยฒ. Now here we could take pq as a common factor. So in brackets we have p minus q. So from here we obtain xยฒ as pq into p minus q divided by pยฒ minus qยฒ. But the denominator could be further factorized...so we have xยฒ is equal to pq into p minus q and the denominator could be split as p plus q into p minus q. Now p minus q gets cancelled. So we have xยฒ equal to pq upon p plus q. So we have obtained x square. Let's check with the options now. pq upon p plus q. No we have pq upon p minus q over here. So the correct answer is Option D: none of these.
๐๐๐จ๐ฎ๐ญ ๐๐๐ญ๐ก๐ฌ ๐๐ฅ๐๐ญ๐ญ๐๐ซ
๐๐ฆ๐ฉ๐จ๐ซ๐ญ๐๐ง๐ญ ๐๐ข๐ง๐ค๐ฌ
๐ ๐จ๐ซ ๐ฆ๐จ๐ซ๐ ๐ข๐ง๐๐จ๐ซ๐ฆ๐๐ญ๐ข๐จ๐ง
๐ฑ๐๐๐ ๐๐ on Facebook at @mathscart.
๐ญ๐๐๐๐๐ ๐๐ on Twitter at @maths_platter
๐ซ๐๐๐๐๐๐๐ ๐๐๐๐๐ on our telegram at @mathsplatter.
And remember, you can learn anything. For free. For everyone. Forever. #YouCanLearnAnything
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