Chapter 5 : Exercise 6 : Python tutorial 106

Guys please help this channel to reach 20,000 subscribers. I'll keep uploading quality content for you.

Python is easy programming language to learn and anyone can learn it, and these tutorials are 100% free in hindi.

You can share this playlist with your brother, sisters and friends. This will surely add some values to their life.

If you follow this complete playlist of python tutorial surely you will learn everything about python programming language.

This is chapter 5 exercise 6

[NoorMuhammad-dtkf]

test = [1, 2, 3, [1, 2], [1, 2, 3], []]

def list_count(li):
count = 0
for i in li:
if type(i) == list:
count +=1
return count

print(list_count(test))

[rangesh]

def check(l):
counter=0
for i in l:
if type(i)==type(l):
counter+=1
print(f"Total lists inside list is : {counter}")



numbers=[1, 2, 3, [1, 2, 3], ["hello", "how", "are", "you", "???"], [3, 2, 1]]
print(f"Entered List:{numbers}")
check(numbers)

[yu_a_vi]

def list_count(x):
a= 0
for i in x:
if type(i) == type(x):
a +=1
return a
x = [1, 2, 3, [1, 2], ["You"]]
print(list_count(x))

[siddharthmalviya]

def check_number_of_list(lst):
count = 0
for item in lst:
if type(item) == list:
count += 1
print(count)


check_number_of_list([1, 2, [3, 4, 5], [12, 3]])

[subhashriroy]

x= [ [1, 2, 3, 4, 5], [2, 3, 4, 5, 6], 1, 2, 3, 4, "Subhashri"]
def common_(y):
count=0
for i in y:
if type(i)==list :
count+=1
return count

print(common_ (x))

[ashishnayke]

def count_list(l):
lst=[ ]
for i in l:
if type(i) == list:
lst.append(i)
return len(lst)
num=[1, 2, 3, [4, 5], 6, [7, 8], 9]
print(count_list(num))

[MRGolum]

list1 = [1, 2, 3, 4, [5, 6, 7], [8, 9], [5, 6, 7], [8, 9]]
def check_lists_in_list(list1):
count = 0
for item in list1:
type_of_item = str(type(item))
if type_of_item == "<class 'list'>":
count += 1
return count

[gauravmarathe]

106 Excersie

def
count=0
for lst in given_list:
if(type(lst))==list:
count+=1
return count

mix_list=[1, 6, 5, [1, 8, 9], [8, 6, 9]]

[dipankur]

mixed= [1, 2, [3, 4], [5, 6]]
def count_lists(x):
num=0
for i in x:
if type(i) is list:
num+=1
return num
print(f"You have {count_lists(mixed)} list(s) inside your list.")

[Navneetkaur-yzxg]

Def howmuchlist(l):
For sublist in l:
Return sublist

Num =[1, 2, 3, [4, 5, 6, 7], [8, 9, 10, 11, 12] ]
Print(howmuchlist(num))

[TheAshu]

multi_Dimention_list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
count_time = 0
def chck_multiDimention(lst):
global count_time
for i in lst:
count_time+=1
return count_time

[zeeshanakram]

sir! here is my solution:

list1 = [1, 2, 3, [1, 2], [3, 4]]
def count_lists_inside_list(l):
count = 0
for i in l:
if type(i) == list:
count+= 1
return count
print(f"number of sublists in list1 are:\

[shamimsarker]

ara = [1, 2, 3, [23, 22], [3.12, "Shamim", "Abdullah", "8982"], [3, 2, 1, 2], ["Virat", "Mashrafe", "Dhoni", "Anushka"]]
sum=0
for i in ara:
if(type(i) == list):
sum+=1
print(sum)

[harshitngupta]

How can I take these type of input from user?

[TheDev]

def list_finder(l):
total = 0
[total := total + 1 for i in l if type(i)==list]
return total

[satyabratanayak]

Input=["baseball", "a, all, b, ball, bas, base, cat, code, de, e, quiz, z"]
Output="base, ball"
I need answer for this program can anybody plz help me out