Tamilnadu New Syllabus Class 12 Maths | Example 6.4 | Applications of Vector Algebra

Class 12 | Example 6.4 | Applications of Vector Algebra | வெக்டர் இயற்கணிதத்தின் பயன்பாடுகள்
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CHAPTER 6 – Applications of Vector Algebra
6.1 Introduction
6.2 Geometric Introduction to Vectors
6.3 Scalar Product and Vector Product
6.4 Scalar triple product
6.5 Vector triple product
6.6 Jacobi’s Identity and Lagrange’s Identity
6.7 Different forms of Equation of a Straight line
6.8 Different forms of Equation of a plane
6.9 Image of a point in a plane
6.10 Meeting point of a line and a plane
#ApplicationsofVectorAlgebra#class12Mathstamil#வெக்டர்இயற்கணிதத்தின்பயன்பாடுகள்

[subithra]

Hi sir I am a great fan.. and I like to watch alex maths video... thank you for uploading these videos...

[dhandayuthapanip]

Please upload one marks for 5th chapter Sir. Otherwise I have to memorize it. My school teachers won't teach

[jawaharls]

sir.. நீங்க இந்த மாதிரி system la class எடுக்க.. என்ன software use பண்றீங்க... plz tell me sir.. its very use full for my students.

[vanithaanuja]

Hi sir
Neenga learn panrathu romba easy a under stand aaguthu tq so much sir

[akeditz]

alex sir, your r the pride of our nation

[nathanloga]

Bro Neenga AB×BC=CA×AB
Andha equation(2) la formula vachi panninga adhumaadhiri 3 equation ku panna laama

[thangamborewells]

a*b=-b*a OK but AB*BC is not equal to -CA*AB

[safeek]

Sir one help 1 chapter full aah nenga mudichingana antha chapter formulas aah separate aah pothunga sir nanga yella formulasu theliva learn pannika mudiyu plz sir....😔

[BharathKumar-jjvo]

Sir, important sums for Firstvolume book

[deshihas]

Gurunatha.... Chapter 6 concept explanation guruve.... Plzzz puriyala ஐயா...

[janakiramanraman]

Put the important questions or concept wise questions for quartely or volume 1 sirr

[madhunanjappa]

I like ur maths ☺when the homework given i will watch ur video🤩

[abdjr.]

Can't use vector while typing
4.40 AB×BC not equal to -AB×CA
CA×AB=-AB×CA

solution:
BC×(BC+CA+AB)=0
BC×BC+BC×CA+BC×AB=0
BC×BC=BCBCSin0°=0
BC×CA+BC×AB=0
BC×CA=-BC×AB
BC×CA=AB×BC→1
×by AB
AB×(BC+CA+AB)=0
AB×BC+AB×CA+AB×AB
AB×AB=ABABSin0°=0
AB×BC+AB×CA=0
AB×BC=-CA×AB
AB×CA=-CA×AB
AB×BC=AB×CA→2
AB×BC=AB×CA=BC×CA

caSinB=cbSinA=absinC
÷by abc and rearrange it
SinA/a=SinB/b=SinC/c
Hence proved√
-C5R

[nattu]

Sir chapter 6 theorems upload pannunga pls

[biology.]

How came? diagram π -A, π-B, π-C sir explain pls

[marjunan]

Can we do vector product of CA instead of AB or BC sir?

[thoufeekrahuman.s]

sir why are we taking pi-A, pi-B, pi-C

[gayathrivinayagam]

Sir send some important question paper sir pls