Trigonometric Ratios of Complementary Angles | Trigonometry - 3 | Vedantu Math Infinity Class -10

Trigonometric Ratios of Complementary Angles | Trigonometry - 3 |Vedantu Math Infinity Class -10. In today's session, Mathematics Master Teacher Deenbandhu Pandey Sir takes you through the Trigonometric Ratios of Complementary angles, as it is one of the most important and scoring topics in Maths, CBSE Class 10 of NCERT Maths Books. Deenbandhu Sir enlightens you with CBSE Class 10 exam preparation strategy for Maths with in-depth explanations and how to revise crucial topics. This session will mainly be around the Important Question of Trigonometric Ratios of Complementary angles, hand tricks on how to find values of Trigonometric Standard Angles within seconds, Trigonometric Short tricks, Trigonometric ratios of Complementary Angles.

#TrigonometricRatios #Trigonometry #complementaryangles #angles #CBSE #Vedantu

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Trigonometric Ratios of Complementary Angles | Trigonometry - 3 |Vedantu Math Infinity Class -10. In this video, Deenbandhu Pandey Sir will explain from basic and the best method to solve complementary angles problems. No need to write or memorize trigonometric values anymore. In this video, you will learn the easiest way to learn Trigonometric Ratios of Complementary angles values and trigonometry formulas.

About Mathematics:
Math isn't only about numbers, math skills are found in our everyday life, puzzles, and games too. Take a look at this Vedantu Math Infinity - Class 10 - "Trigonometric Ratios of Complementary Angles | Trigonometry - 3 |Vedantu Math Infinity Class -10."

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[mathinfinity-ththmaths]

Diwali Sale from 7th Nov to 11th Nov➡️Apply the Code “YTPRO” & Get a 50% Discount!!

[Sana]

Thanks to vedantu's each and every channel to provide such amazing stuff's to us with this master teacher's and content

[gaurangimishra]

Tysm sir 😊
The concept is clear😊
Amazing session 💕

[siyachandel]

Amazing explaination sir 👏👏
Is anyone here For year 2021-22
Although its deleted but
THIS TOPIC IS GONNA HELP IN FUTURE CLASSES

[eknathmote]

Ans :- Cosec 31 - sec 59 = sec(90 - 31) - sec 59 = sec 59 - sec 59 = 0 your session sir thankyou very much ♥️♥️

[ritudubey]

Sir solution to homework question should be 0
Cosec 31°=sec 59°
Now, sec 59°-sec 59°=0

[Kk_]

Sir bhot mast padhaya and thanks for telling my mistake lol sir

[mahakjain]

TAN B
SIR IT SHOULD BEEQUAL TO COT A=TAN B

[cosmicblox]

What kaho Haan...how many times u repeat this

[satvikdixit]

He looks almost same as Rohit Sharma 😀😀😀😀

[sakshipandey]

LOL SIR 💜😊
U teach so damm amazinggg !!

[sureshchand]

Lot of drama and wastage of time is there rather than focusing on teaching ....

[overachiever]

Sir please see this I have done the question in a other way is this correct.q.no.3
sin(B+C)/2=cosA/2
sin(180-A)/2=cosA/2
sin(90-A/2)=(sin90-A/2) because, cosA/2. s =sin(90-A/2)
SIR PLEASE SEE THIS

[iqlipse]

Sir aap faltu ka time waste karte hai bas chat ka reply hi karte rahte hai bilkul accha nai padhate

[deepanshsingh]

Sir app ye barbaar hao khena or bulwana band karo

[abhayrajmendhe]

Done ., .done are u mad bar bar type karte batenge kay