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Solve a Linear Trigonometric Equation in Sin(x) and Csc(x) (Degrees)
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The trigonometric equation to be solved is 2sin(x)+csc(x)+3=0. This is a linear trigonometric equation with two different trig functions that are reciprocal functions. The steps to solving this type of equation are: (1) Use a reciprocal identity to write the equation in terms of one trigonometric function. (2) Multiply the resulting rational equation by the LCD. (3) Solve resulting quadratic equation in one trigonometric function. On solving this equation, the solutions had to be checked against the restriction of the denominator can not equal zero. Three good solutions were obtained.
Timestamps
0:00 Introduction
1:00 Steps for Solving This Type of Equation
1:30 Use csc(x)=1/sin(x)
2:08 Multiply by LCD
4:21 Factor Quadratic Equation
5:55 Use Unit Circle
Timestamps
0:00 Introduction
1:00 Steps for Solving This Type of Equation
1:30 Use csc(x)=1/sin(x)
2:08 Multiply by LCD
4:21 Factor Quadratic Equation
5:55 Use Unit Circle