Remove Duplicates from Sorted Array (With Algorithm & Python Code)

Remove Duplicates from Sorted Array (With Algorithm & Python Code)

-~-~~-~~~-~~-~-
Please watch: "LRU Cache (With Python Code) "
-~-~~-~~~-~~-~-

[AnilKumar-wflb]

Mam what will be the output for 1-2, 2-3, 3-4, 4-5, 5-6 test case

[barulli]

by creating a temporary array, arent we breaking the in-place condition?

[missionkillgaming]

We have to remove duplicates no so what if we first convert into set and then append to empty list. Then also its working.

[tinasurlan]

but range function goes up to but doesn't include the second value. For example: range(0, 5) = 0, 1, 2, 3, 4

[prashantjena]

How it is removing duplicate...no. 3 does not have duplicate then too it is removing

[badsah]

arr = [1, 2, 3, 3, 4, 5, 5, 6, 6]

# Remove duplicates
arr_without_duplicates = list(set(arr))

print(arr_without_duplicates)

[piyushsharma]

def dropdup(ls1):
count=0
dct={}
for i in range(len(ls1)):
if ls1[i] not in dct.values():
print(dct)
dct[count]=ls1[i]
count+=1
return list(dct.values())

[markkojo]

def remove_duplicates(a):
lista= []
for x in a:
if x not in lista:
lista.append(x)
else:
continue

return lista


if __name__ == "__main__":
a=[1, 1, 2, 2, 2, 3, 4, 4, 4, 5, 5]
print(remove_duplicates(a))

[pygal]

Mam Hw do we do for unsorted array, a video on Tat pls

[AbdulRehman-eezc]

can't we use
return list(set(arr))

[sumitwagh]

why don't you run the for loop and write the condition
new = []
for i in arr:
if i not in new:
new.append(i)

[meetvardoriya]

one liner: list(set(number_list)), where number list is the list of numbers!

[AbdulHaseeb-oteb]

ahh we can just convert list into set and it automatically gets the unique entries

[puranjaigupta]

It is not a correct solution for every case.