I was just reading the question and the bro even solved it 😓🤯
pratyushkhandelwal
That other guy was such a good sport too
mingodingo
Not saying I am as fast but a simpler solution would be:
Ok so 3√3 in the beginning is "1" power
Then 27^4 is basically 4 times whatever power of 3√3 27 is, so that's 4*2="8" (3√3 squared is 27)
And finally 9^3 is 4/3 * 3 (since, 9 is 3^2 and 3√3 is 3^1.5, so 2 is 4/3 of 1.5) = "4"
√3 × 3 × 9³ × 27⁴ = (3×√3)^x
3^1/2 × 3¹ × (3²)³× (3³)⁴ = (3¹×3^1/2)^x
Using basic exponental rules
(a^b)^m = a^bm
a^b × a^c = a^(b+c)
3^(3/2) × 3⁶ × 3¹² = (3^(3/2))^x
6 = 18/3, 12 = 36/3
3^(3/2) × 3^(18/3) × 3^(36/3) = 3^(3x/2)
3/2 + 18/3 + 36/3 = 3/2 + 54/3 = 9/6 + 108/6 = 117/6
3(117/6) = 3^(3x/2)
Bases are same so exponents are equal
117/6 = 3x/2
117/6 × 2 = 3x/2 × 2
117/3 = 3x
117= 9x
x = 13
Final Answer→ x = 13
(I probs did a few longer steps, but its correct)
idkidc
Even if I remembered the video wouldn’t answer this fast
ajtv_ag
I don't know how I got this formula but it works.
√3×3×9³×27³=(3√3)¹³
√3×3¹×3⁴×3⁶=(3√3)¹³ I think I was wrong here.
1+4+6=13
(3√3)¹³
Again I answered correctly but the method was wrong
Kenzie_SLR_ESPB
HE IS SO FAST I SOLVED IT BUT DAMN THATS CRAZY FAST
Chez-fx
the guy is talking really slow. the reader already knows what you need to find denoted by classic "x". hence all that talking is kinda distraction.
