How to Implement Binary Search from Scratch in Javascript

In this video, we cover:
0:24 how binary search works using a practical example
1:59 how to pseudocode an implementation
5:04 an iterative solution in javascript
9:20 a recursive solution in javascript
12:56 time and space complexity analysis

[archiekesseler]

Hey. Calculating mid as (left + right) / 2 will lead to overflow for large enough input size. Instead, it's recommended to find it as left + (right - left) / 2 which takes care of the overflow.

[abhisheksrivastava]

such a smooth explanation! will never forget binary search.

[kduisheev]

Really liked Helper function, Thanks @Coderbyte

[jhonymaurad]

By far the best video explanation! Clear and and well explained.

[driveinspire]

Thank you so much mam.
Very cool teaching mam totally understandable

[Ringo_Panda]

Thank you for explaining this so clearly!

[ВладимирАндреев-фт]

it will better work if you put in left = -1 and right = array.lenght in the begin))))

[as]

Thank you! But for the iterative way, shouldn't we use "while (left <= right)" instead of "while (left < right)"? So that we can find the target at index 0 or index length - 1.

[pendyalaabhishek]

is there a inbuilt function for binary search in js?.

[minnuss]

So, what is faster, array.indexOf(target) or this code...

[numantayyebi]

binarySearch([1, 2, 3], 1)
this will return false. does anyone know why? the middle, start and end all are at the same spot. but it will not evaluate if(arr[mid] === target) condition.