Digital SAT Math - Desmos Lesson #17 Domain Restrictions

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Check out this calculator lesson - Digital SAT Math Desmos Lesson #17 Domain Restrictions - created by an 800 SAT Math scorer. Learn how to use Desmos to solve questions more efficiently and even get answers to questions you know nothing about.

You can learn more about Desmos by watching the Learn Desmos playlist here:

You can download the Bluebook app to take Digital SAT Practice Tests here:

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could you tell me, how did you get -16 in the first task?

dayletba
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I always fpound these questions so hard every time i encountered i always skipped them but now you taught me what they really ask for.Thank you so much

Footbal_gameslife
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Thank you for these videos! I increased my math section from 710 to 800 just through your playlist on how to use the Desmos calculator. It helps me go through problems way faster and be sure about my response. Cheers!

mmmmmmmm
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thank you so much, you saved me alot of time it will be my first time taking the sat next week and math wasnt always my strong point and by watching you i m confident now entering the sat

ramadankassem-hk
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Thank you so much for these lessons, my sat is next week and this course helped a lot with questions I was stuck on for weeks.

yara
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Hi again Kyle, In the last question, can you explain me where can I find, use, or reach the coefficents (x-4, x+1) in the equations to be sure? Thank you so much for your help <3

ardayilmaz
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Hi! regarding the first question do we always have to change the grid and write what you wrote for ex 0 is less than or equal to x and so on?

ZainaAbdullah-iv
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which lessons do i watch if i have trouble with khan academy's first unit the linear chapter? along with radicals and graph?

aino
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this might be a really stupid question bcs i just learned the regression feature on desmos, but when i put the 2 coordinates in q1 in a table on desmos and then use regression for y~a(x-h)^2 +k why dont we get the right equation? i know this is very simple to do by hand but i wanted to learn in what questions i could use it. do we get the wrong answer because we have put the vertex as x1, y1 in the table when they are actually h, k? also could u share the video in which uve done more of these projectile questions? thank you!

AkshitaSingh-ls
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May I ask why in the last question, the min of f(x) is f(1) but the min of g(x) is f(5) please? I thought that it's always x=1 that both fuctions reach their minimums

heavalteria
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why isn't the answer 177ft? because if it reached 225ft max from being launched at 81ft that means 225-81=144. so it launched 144ft, then 144ft divided by 3 = 48. So per second it launched 48ft. then since the question is only asking 2 seconds then that means 48x2= 96 then add the 96 to the original platform 81ft=177 so therefore shouldn't the answer be 177? please correct me if i'm wrong

bethanyberi
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15:16 in this part, the coefficient or constant has to be directly given to us for the condition to be valid, right?
For example, if the minimum value was 1.6, would the function I be true, because 2 times 0.6 equals 1.6?

aavashtiwari.
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Can you please make video over scatterplots problems in DSAT?

rareraju
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Thanks for the video. How can we solve question 2 and 3 without demos?

habibahrashwan
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thank you for this! i just have one doubt, wouldn’t it be easier to use regression for the first question instead of manually finding A and then putting it in desmos?

rodrigosol
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for people who watched other videos from him, for question 1 u can also use regression to solve it. but you'll need a 3rd point.

solaracrafts
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i am pretty sure for the questions you showed exponents arents supposed to count since it says constant or coefficients. Correct me if im wrong please.

Clinksys
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can we solve geometry questions with Desmos??? if yes can you please make a video about how to solve them, because your videos have been super helpful. THANK YOU A LOT.

mabarcalona
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hi, can you please explain where the 16 in the first question came from.

nightlifechingu
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for the first question aren't you supposed to subtract 81 from 209 since the object was launched from a platform 81 feet in the air

antonbln