LeetCode 94. Binary Tree Inorder Traversal in Java (Stack-Based Solution)

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00:00 - Introduction
00:07 - Whiteboard Walkthrough
04:59 - Edge Cases and Complexity
07:40 - Java Code Implementation
12:42 - Conclusion

Welcome to LeetCode LevelUp!

In today’s video, we solve LeetCode Problem 94: Binary Tree Inorder Traversal using Java. This problem is a core interview question that helps evaluate your understanding of tree traversal and stack data structures. We’ll implement an iterative inorder traversal with a stack, which is optimal for space in this problem.

We’ll cover:

The problem statement and key ideas for approaching binary tree traversal iteratively.

A whiteboard walkthrough explaining how the stack manages node traversal.

Detailed Java code implementation to perform inorder traversal and capture node values in a list.

Important edge cases like empty trees and single-node trees.

Complexity Analysis:

Time Complexity: O(n), where n is the number of nodes in the tree, as each node is visited once.

Space Complexity: O(h), where h is the height of the tree, due to the stack’s depth for storing nodes.

This is a space-efficient and optimal iterative solution for inorder traversal.

🔥 Be sure to explore more coding challenges, algorithms, and interview preparation in Java to level up your problem-solving skills and ace technical interviews!

📌 Let’s connect on LinkedIn: / oliver-redican-84996193

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Комментарии

Great breakdown Oliver! This explanation of binary tree in-order traversal was really clear and approachable.

I especially liked how you walked through each step of the iterative approach with the stack and emphasized the time and space complexities.

The edge cases were also a fantastic addition, making sure viewers understand how to handle null roots and single-node trees.

Your attention to detail in explaining each action with the stack was super helpful in demystifying the traversal process for learners.

Edit:
Looking forward to more videos like this—keep up the awesome work!

islandblaze

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