Python Tutorial in Urdu | Hindi | Validating Users input in Python | Data Entry Validation in Python

In this video you will learn about Python Tutorial in Urdu | Hindi | Validating Users input in Python | Data Entry Validation in Python

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[Shashlick-chanel]

Sir, V v well explained 👏🏼👏🏼👏🏼👏🏼👏🏼👏🏼👏🏼bravo

[peacemonger]

first_number = input("Enter first number: ")
result = ''
if first_number:
second_number = input("enter the second number :")
if second_number:
first_number = int(first_number)
second_number = int(second_number)

print(result)
else:
print("Second number is required!")
else:
print("First number is required!")

[Pplay]

AssalamOalaikum
Sir, here's my first assignment

First_Number = input("Enter First Number")
if First_Number:

Second_Number = input("Enter Second Number")
if Second_Number:

Result = First_Number + Second_Number * First_Number
print(Result)
else:
print("Second Number is required")
else:
print("First Number is required")

[aliusama]

Asalamulakum SIr How are u, SIr me apne program me "def main ( ):" statament use kr raha hun jump back k liye kia ye approuch sahi he ?

[shortclipentertainment]

I do assignment

First _number =input ("enter first
number")
Second_number=input ("enter second number")
Result=" "
If first_number:
If second_number:


Result=(f" {first_number + second_number}
Else:
Print ("second number required")
Else:
Print ("first number and second number both are required")
Print (result)

[haidrium]

result = ''
first_number = input('Enter first number here : ')
if first_number:
first_number = int(first_number)
second_number = input('Enter second number here : ')
if second_number:
second_number = int(second_number)
result = first_number + second_number * first_number
else:
print('second number is
else:
print('Missing first
print(result)

Bhai I changed approch a bit .
As you can see on the top,
Firstly, i asked for input for number 1 and after that i restricted that if that number exsist ask for second number if not then simply go to else statment of first IF statement.

But its still working xD

[masterconsultants]

# Validation
first_number = input("Enter First Number: ")
if first_number:
first_number = int(first_number)
else:
print("First Number is Required")
second_number = input("Enter Second Number: ")
if second_number:
second_number = int(second_number)
else:
print("Second Number is Required")
if first_number and second_number:
result = 0
result = (first_number + second_number) * first_number
print(result)
else:
print("First And Second Number Both are Required")

[umar]

first = input("Please enter first number")
second = ''
if first:
second = input("please enter second number ")
else:

print("First Number is required")

if second:
first = int(first)
second = int(second)
result = first * second
print(result)
else:
print("Second number is required")

[pixemsoft]

A.o.A sir ap ki paython serious bht achi chal rai he. Me b ab proper Paython ki tarf turn lene lga ho but ak chez bta de paython ka jab me professional level pe jao ga to kis trha ke projects pe work krne ke lye python kam aye ge...Means jese ham POS and es trha ke applications banty he python me b esi trha ka kam ho ga kya and Uniq thing kya ho ge paython me agr ham ese .Net ke sath compare kre to

[AMARDEEPCHINTU]

how to take age as integer ( 24 ) not as ( twenty four ) string. i want to validate the input only the integer value not the text or string, if the user entered string like twenty four then i need display "please enter the number not the text"

[muhammadzaheersajid]

validation concept


number1 = input("Please enter first number : ")
number2 = input("Please enter second number : ")
result = 0
while number1 =="" or number2=="":
print("Please enter both number")
number1 = int(input("Please enter first number : "))
number2 = int(input("Please enter second number : "))

else:

result = int(number1) + int(number2)
print(result)

[naumantariq]

*Aoa*
*Kindly check My Assignment*


first_Number=input("Enter First Number: ")
if first_Number :#here we are validating the statement

first_Number = int(first_Number)
else:
print("First Number is Required")

second_Number=input("Enter Second Number: ")
if second_Number:


else:
print("Second Number is Required")

if first_Number and second_Number:
result = ' '

result=(first_Number + second_Number) * first_Number
print(result)

else:
print("First And Second Number Both are Required")

[aroosmian]

if first_number and second_number:
first_number = int(input("Enter First number: "))
second_number = int(input("Enter second number: "))
result = ''
result = first_number + second_number * first_number
else:
print("First and Second number are both required: ")
print(result)


not giving feedback this code giving error

[shobiahmed]

a=int(input("enter number"))
b=int(input("enter number"))
result=0
if a and b:
result=a+b
print(result)
else:
print("plz enter number")
sir its not cheecking...why

[muhammadhamzaatif]

Sir I also tried to write this program in another way to eliminate any type of error but I could not remove it & program is


first_number = input("Enter the First Number : ")
second_number = input("Enter the Second Number : ")
result = " "


if first_number:
first_number = int(first_number)


if second_number:
second_number = int(second_number)


else:
print("First Number & Second Number both are needed.")


result = first_number + second_number * first_number


print(result)

After writing this program, the error occurs in line no 13 is


Atif/Python/New Python User"
Kindly enter the First Number :
Kindly enter the Second Number :
First Number and Second Number both are needed.
Traceback (most recent call last):
File Atif/Python/New Python User", line 14, in <module>
result = first_number + second_number * first_number
TypeError: can't multiply sequence by non-int of type 'str'

Process finished with exit code 1

Sir Plz also find it's solution by debugging this error and comment it's solution

[muhammadhamzaatif]

Aoa Sir.Sir I write this program of the assignment that is given below


first_number = input("Kindly enter the First Number : ")
second_number = input("Kindly enter the Second Number : ")
result = " "


if first_number:
first_number = int(first_number)
else:
print("First Number is needed.")


if second_number:
second_number = int(second_number)
else:
print("Second Number is needed.")


result = first_number + second_number * first_number


print(result)


Sir type error comes in the line no 15 and error is that python interpreter is not concatenating both integer numbers into string by sequences. I don't understand why this error is showing in the output screen.Sir please debug this error and find it's solution to me. I shall be very thankful to you.

[abdullahbirjees]

sir kindly check my program:
first_number = input("enter first number: ")
second_number = input("enter second number: ")
result =""
if first_number:
pass
else:
print("first number is required:")
if second_number:
pass
else:
print("second number is required:")
if first_number and second_number:
first_number = int(first_number)
second_number = int(second_number)
result =
print(result)
else:
print("both numbers are required for this operation")

thankx alot.

[nabeelahmed]

Assalam Alaikum Sir!! here is my code it is not working please correct me where i'm wrong.. I know python is a interpreter language..






first_number = 0
second_number = 0
first_number = int(input("Enter first number: "))
if first_number == 0:
second_number = int(input("enter the second number :"))
pass
if second_number == 0:
pass
else:
print("Second number is required!")
else:
print("First number is required!")

if first_number and second_number:
print(f"result =
else:
print("Both values are required for this operation!")

[usmanimtiaz]

After entering correct username and password it still show error username and password is incorrect. You not tell how to fix this issue.