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What will be the output of the above python code? #python #coding #shorts

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This Python code defines a function named func. Here's a breakdown of what the code does:
def func(x, y, z=0):: This line defines a function named func that takes three parameters: x, y, and z. x and y are required parameters, while z is an optional parameter with a default value of 0.
return x - y + z: Inside the function, it returns the result of subtracting y from x and then adding z.
print(func(5, 2, 3)): This line calls the func function with arguments 5, 2, and 3, respectively, and prints the result of the function call. Since x is 5, y is 2, and z is 3, the result will be 5 - 2 + 3, which equals 6.
print(func(5, 2)): This line calls the func function with only two arguments: 5 and 2. Since z is optional and has a default value of 0, it will use 0 for z. So, x is 5, y is 2, and z is 0. The result will be 5 - 2 + 0, which equals 3.
So, when the code is executed, it will print:
6
3
This code demonstrates the usage of default parameter values in Python functions.
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def func(x, y, z=0):: This line defines a function named func that takes three parameters: x, y, and z. x and y are required parameters, while z is an optional parameter with a default value of 0.
return x - y + z: Inside the function, it returns the result of subtracting y from x and then adding z.
print(func(5, 2, 3)): This line calls the func function with arguments 5, 2, and 3, respectively, and prints the result of the function call. Since x is 5, y is 2, and z is 3, the result will be 5 - 2 + 3, which equals 6.
print(func(5, 2)): This line calls the func function with only two arguments: 5 and 2. Since z is optional and has a default value of 0, it will use 0 for z. So, x is 5, y is 2, and z is 0. The result will be 5 - 2 + 0, which equals 3.
So, when the code is executed, it will print:
6
3
This code demonstrates the usage of default parameter values in Python functions.
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