3.5 and 3.6 - Implicit Differentiation + Inverse Trigonometric Functions and Their Derivatives

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Ms. Roshan's AP Calculus AB Videos -- Based on Stewart's Calculus: Concepts & Contexts
  1. Stacey Roshan
  2. derivatives
  3. Trigonometry (Field Of Study)
  4. Implicit Function
  5. Inverse Trigonometric Functions
  6. Derivative (Literature Subject)
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So at 10:46, one of the points is (0, 0) because when we solved for x, we got x= 0, and 3root(16). And since 1/2(0)^2 is 0 that would be our y for when the x = 0 right? This this mean both points (0, 0) and (3root(16), 1/2(16)^3/2) are both valid horizontal tangent line points, or is it just one of the points?

whoskwabi
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its 5am where I live, and I have a midterm today that includes 4week material, YOU ARE SAVING MY

Sara-srop
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13:41 - How did you factor out a -1 from [ cos(x+y) - 2ycosx ] if only [-2ycosx] has a negative?

whoskwabi
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I'm a first year student at a university and i didn't understand shit regarding this thank you for your awesome lecture

nduduzoshabalala
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This is a great topic Stacey. I am glad you explained this. It helps me learn.

danhobson
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Hi Stacey I love your videos so much! I was wondering if you made any videos similar to the Parametric Curves in 1.7?

toMouseHive
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Hi Stacey! 20:27 where did the sin come from? There was no sin originally

mojo
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This is PERFECT! You posted these just when I needed them. Thank you!

laurenrogers
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You are the best, finally helped me understand calculus!

ssschase
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These videos are awesome. Thank you so

tae-wankim
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In Example 5 "I don't like to use the quotient rule where I don't have to."

Use the reciprocal rule instead: (1/f[x])' = - f'[x]/(f[x])^2.

johnnolen
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damn i wish i was derivative of y so cute asian math nerd girl would call me baby

georgianultraimperialistor