GCSE Maths - How to Solve Algebraic Equations (Part 3 of 3) #45

This video covers how to solve harder algebraic equations, which only have variable on both sides of the equation and multiple operations. For example 2x + 3 = 5x - 9

This is part 3 of our 3 part series on solving algebraic equations.

This video is suitable for maths courses around the world.
KS3 - All on your course
GCSE Foundation - All on your course
GCSE Higher - All on your course

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[Cognitoedu]

If you’d like to practise the material covered in this video, check out our platform at www.cognitoedu.org - it's totally free, and has been built to make learning and revision as easy as possible. The main features are:
- Lessons organised by topic, only the lessons relevant to your specific exam board and tier are shown.
- Automatic progress tracking. Progress bars tell you what you’re doing well at, and what you need to spend some time on.
- Practise quizzes so you can test your knowledge. You can quiz yourself on any combination of topics you like.
- A huge number of fully-hinted questions that take you step-by-step through some of the trickiest calculations & concepts.
- A comprehensive bank of past exam papers, organised both by year, and also by topic.

Amadeus & Tom

[Tafara-ju]

You are the best teacher i've ever met online❤

[henryhsil]

Video from cognito can't resist watching... 😃

[noorazlina]

Very good explanation. Easy to follow. Please make a video on solving fractional equations :)

[-karol-]

i was just wondering, are u also going to be doing the further maths course?

[LadyGemini]

the same problem for me again...i understand all of it apart from with 2X + 15 = 5X why we are not dividing on both sides instead of doing -2x?

[dizzygreencow]

I really struggled wrapping my head around the last 2 equations. I get the principle of isolating a letter and a number and the principle of 'mirroring' actions on both sides of the equation. I struggled to work out which of the numbers I should be working on. For example, in one of the equations you reach a point where you get -5 =7 2a . In order to solve it, the video subtracts the 7 to leave -12 = 2a. Will it always be the number on the 'inside' of the equation that requires an action to solve it? Kind of like trying to keep the 'outside edges' of the equation and trying to remove the 'inner' number. If that's not the case, could someone please advise of how to work out which number needs an 'action' in order to solve? Thanks.

[newtopazhawk]

What is there are two separate Xs in the first bit like 3X²+6x-5=0

[A_rbLOx_Fan]

Question: So x can be a negative number, right? Because in your last video you said about having to make x positive instead of the number.

Suggestion: You could probably make a video about the type of division with ( ) and ÷ as well. But thanks for the rest! They still helped!

[neel]

What grade are these questions targeting? Around 4-6?

[xelessgaming]

My question is why did you decide to remove the -12 also from the first example

[mbtoure]

I only understood at the first example my teacher makes this logical

[theinternationalshop]

they dont teach these things much in school

[thomastuchel]

i dont get why they teach this shit in school its confusing af and when am i going to need this in my adulthood