From the top of a tower, a particle is thrown vertically downwards with a velocity of \( 10 \mat...

From the top of a tower, a particle is thrown vertically downwards with a velocity of \( 10 \mathrm{~m} / \mathrm{s} \). The ratio of the distances, covered by it in the \( 3^{\text {rd }} \) and \( 2^{\text {nd }} \) seconds of the motion is (Take \( g=10 \mathrm{~m} / \mathrm{s}^{2} \) ) [AIIMS 2000; CBSE PMT 2002]
(a) \( 5: 7 \)
(b) \( 7: 5 \)
(c) \( 3: 6 \)
(d) \( 6: 3 \)