951. Flip Equivalent Binary Trees | Tree | Binary Tree | DFS | Recursion | O(N) | LeetCode | Medium

In this video, we’ll explore a C++ algorithm that checks whether two binary trees are flip equivalent. A pair of trees are considered flip equivalent if they have the same structure, except that any number of non-leaf nodes can have their left and right children swapped.

We’ll dive into the code implementation for the flipEquiv function, which takes two binary tree roots (root1 and root2) as input and determines if they are flip equivalent. The function utilizes recursion to compare the trees at each level and returns true if they meet the equivalence conditions. Here’s a breakdown of the approach:

Base Case Check:

If both nodes are equal (including if both are NULL), return true.
If one of the nodes is NULL or their values are different, return false.

Recursive Step:

Check if the left and right children match directly or if a flip occurs (left of one matches right of the other and vice versa).
This algorithm efficiently checks for equivalence in an elegant manner using recursion.

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