w^2 + 12w - 40 = 0; Which of the following is a solution to the given equation?

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Bluebook Digital SAT Practice Test 6, Section 2, Module 2 (HARD), Question 18:

w^2 + 12w - 40 = 0
Which of the following is a solution to the given equation?

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Completing the square (less algebra).
(w + 6)^2 = 40 + 36
w = -6 +/- 2 rad(19)

Desmos requires additional work because of the radical on the answer choices. No easy lunch!

OverclockingCowboy