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If 2^x = 3^y = 6^(-z), then prove that: 1/x + 1/y + 1/z = 0.

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If 2^x = 3^y = 6^(-z), then prove that: 1/x + 1/y + 1/z = 0. In this video, you can learn how to prove exponential equations.
#education #maths #indices
#education #maths #indices