I was starting to think they were getting these formulas via witchcraft...Videos like these are what make online Calc classes passible. Thanks!
SonOfChrist
THANK YOU! You are the ONLY person who explained why -1 and -1/2 doesn't cancel out while the rest of the terms do! Every other video just says "if you keep going, these terms will cancel out" but they do not explain why certain terms cancel out and the -1 and -1/2 doesn't! you are a life saver.
corbenic
Thank you so much! Nobody else is able to explain calculus as well as you!
lilcole
I was struggling like a mofo right now trying to find a clearer logic to this part. I wouldn't budge till it clicked. Now boom, I find this vid lol. You a good man Patrick.
dabooger
Patrick, thank-you for your video tutorials! You've made calculus more accessible to me and I really appreciate all your efforts.
Thank-you Very Much!
DisheveledSuccess
1/(K+1) -> he got this because he stopped at n=5. if you notice there's a 1/6 that hasn't been canceled out. plug in n=5 for k and you get 1/6.
you do the same method for 1/7. 7 is 2 greater than 5 so its 1/(K+2) instead of +1. I think this is how its done from my understanding.
McNoulty
How did u get 1/(k+1) and 1/(k+2)...third video I'm watching on this series telescoping and indent get how do it!!!?!?!???
AyJay
thought I was going insane trying to figure this out, god send video even 10 years later
KeeksRL
Is there a way to find the partial sum of a series directly from the fraction decomposition? I'm working with higher power denominators so it gets a little out control through this method.
jakerahn
Is there a way to change the index? I have to do a problem that starts at n=5 and goes to infinity
marcosaldana
you should do a video on how to prove your formulas up to n+1 via induction as well.
Currently I'm looking for a systematic way of coming about formulas by perhaps manipulating taylor's theorem? Could you point me in the correct direction for the information i am trying to find?
-Maurice
Wooflays
2048.
I won't prove it for you (don't know how because I'm really lazy), but basically what you needed to do was convert it to a summation. In this case, the summation was 1024/2^(n-1), starting at n=1 and going until infinity.
Wolfram can do this for you and confirm that it is indeed 2048.
Flippyxtrne
So is it right that the series converges and approaches (-3/2) ?
still
bro please, can u please find the sum of 1024+512+256+128+....
