Solving Systems of Equations by Graphing (5.1 Big Ideas Math - Algebra 1)

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0:00 - Intro
0:34 - Ex. 1
2:24 - Ex. 2
4:37 - Ex. 3
  1. Mr. G Math
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For the last problem, you could have just plugged in the value of X since it is known after dividing 256/8, which equaled 32? So ... 30X32=960 (rewritten as 960+4y=1040) Then subtract 960 from both sides (rewritten as 4y=80) Then finally divide 4 on both sides getting y=20. Seems much easier this way!

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