459. Repeated Substring Pattern || Java || Leetcode || Hindi

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459. Repeated Substring Pattern || Java || Leetcode || Hindi

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for (int i = 1; i <= n / 2; ++i) {
if (n % i == 0) {
string substring = s.substr(0, i);
string repeated = "";
for (int j = 0; j < n / i; ++j) {
repeated += substring;
}
if (repeated == s) return true;
}
}

shubhaamtiwary
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what is the time complexity of this code ??

hiddenuniverse
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agar aapke code bug hai to fix karke post karo na ki just random tags in screen

javagladiator
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i don't understand why we take n/2? please help

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