Can You Pass Cambridge Math Exam Question? | Math Olympiad | Cambridge Examination Challenge

Hello my lovely family 🥰 🥰 🥰 🥰 🥰

Trust you are doing well ❤️‍🩹

If you like this wonderful MATH Olympiad problem

Please subscribe to my channel 🙏🙏🙏

•Harvard University Entrance Examination
•International Math Olympiad
•Math Olympiad Questions
•Mathematics Education
•Math Problem Solving
•Advanced Math Concepts
•Challenging Math Problems
•Algebraic Expressions
•Nice Square Root Math Simplification
•Nice Algebra Simplification
•Nice Radical Simplification
•USA Mathematical Olympiad
•Germany Math Olympiad
•Japanese Math Olympiad
•Pakistan Math Olympiad
•China Math Olympiad
•Russian Math Olympiad
•Indian Math Olympiad
•Australia Math Olympiad
•Thailand junior maths olympiad questions
•How to solve | Math Olympiad

#matholympiad #algebramath #simplification #exponents #mathproblem #howtosolve #viralmathproblem #maths #matholympiadproblem #mathematics #viralmathshorts #canyousolvethis #canyousolvethisquestion #canyousolve

[parinose]

Right. Degree, 4 > 4 solutions. So, you deliver... However, you could also take the SQR on BS like that : (x-3)^2=- +(7)^2. So, you have 2 cases. Case 1: x^2-6x+9=+49 <> x^2-6x -40=0 > delta=14^2
x1=-b^2+SQR delta/2a =6+14/2=10 (easily found also with x-3=7); x2=-4 Case 2: x^2-6x+9=-49 <> x^2-6x +58=0 > delta =-196=i^214^2 x3=3+7i, x4=3-7i {x1, x2, x3, x4}={10, 7, 3+7i;, 3-7i}

[sam_diron]

i really love watching your videos. thanks for spending your time to make them

[arthurabrao]

Nice question, but the resolution could be more simplified, even a little. However, I really liked the video. Congrats!

[martinaubut]

Now, we are saturday and watching you today is like I was kept in school for a bad behavior in class.... but in better.

[larry]

People keep saying how they can guess some of the answers, which is great, but this is a lesson on how to use the systematic methods of algebra to find the solutions. You might be able to guess on simple ones like this, but a systematic approach teaches how to solve ones you can’t guess.

[busyhandeler]

Bro it will just be easier to power both sides with quarter, that way you will get the answers directly, easily, faster, and save time.

[larry]

Of course, instead of creating the quadratic, x^2-6x-40, you had another difference of squares of ((x-3)^2-(7)^2), which could factored into ((x-3)+7)(x-3)-7), which creates the factors (x+4)(x-10), same result.

[topquark]

The best way is to use a substitution u = x - 3. Then the answer pops out as 4 symmetrical complex roots centered around the point 3 + 0i. I did this in my head in 5 seconds.

[topquark]

10 is the obvious solution, but also -4, and then by geometry you can easily see the other two complex solutions, very little calculation required. Back to the video...

[PawełDąbrowski-nw]

(x-3)⁴ - 7⁴ = 0
((x-3)²)²-(7²)² = 0
((x-3)²+7²)((x-3)²-7²) = 0
((X-3)²+7²)(X-10)(X+4) = 0

Let's set both factors equal to zero

X = 10
X = -4

(X-3)²+7² = 0
(X-3)² = -49
X-3 = ±7i
X = 3±7i