Exercise 1 solution : Python tutorial 121

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This is solution of exercise 1 of chapter 7

[rajeshprajapati]

user = {}
n = int(input("Enter the number"))
for i in range(1, n+1):
user.update({i:i**3})
print(user)

[muzik]

def cube(n):
cubesDict = {}
for i in range (1, n+1):
cubesDict.update({i:i*i*i})
return cubesDict;

[chhiningmagar]

1. Using while loop
num = int(input("enter a number: "))
num_cube = {}
i = 0
def cube_num(n):
i=1
while i<=num:
num_cube[i]=i**3
i+=1
return num_cube
print(cube_num(num))



2. Using for loop

num = int(input("enter a number: "))
numb_cube = {}
def cube_num(n):
for i in range(1, num+1):
numb_cube[i] = i**3
return numb_cube
print(cube_num(num))

[sagarbhagat]

#cube finder
def cube_finder(n):
cubes={}
for i in range(1, n+1):
cubes[i]=i**3
pass
return cubes


print(cube_finder(5))

[Saikiran-tymo]

def cube(n):
a=dict.fromkeys(range(1, n+1), 1)
for i in a:
b={i:i**3}
a.update(b)
return a
print(cube(3))#{1:1, 2:8, 3:27}

[prabhatnagdeve]

my solution:

def cube_finder(n):
cube = {}
for i in range(1, n+1):
cube[i] = i**3
return cube

print(cube_finder(4))

[Dudeinfire]

I did like this: -


Number = 5
def Cube_Finder(N):
Cubed = {

}
i = 1
while i <= N:
Cubed[i] = i*i*i
i += 1
return Cubed
print(Cube_Finder(Number))

[hackerkhan]

MY CODE:



def cube_finder(n):
_dict = {}
for i in range(1, n+1):
_dict.update({i : i **3})
return _dict
print(cube_finder(3))


OUTPUT: 1:1, 2: 8, 3:27

[trigger]

maine fromkeys use kiya..
def cube_finder(n):
dic = {}
for i in range(1, n+1):
dic = dict.fromkeys(i, i**2)
return dic
print(cube_finder(5))

[kripamoypatra]

check This pls..
n=int(input("Enter a no: "))
def cube_finder(n):
d={}
for i in range(1, n+1):
d1=dict.fromkeys([i], i**3)
d.update(d1)
return d
print(cube_finder(n))

[masterdon]

def func(n):
d={}
for i in n:
d[i]=i**3
return d

n={1, 2, 3, 4, 5, 6, 7, 8, 9}
print(f"your key cube is{func(n)}")

[amithsuryan]

is this correct, i am getting same output

def cube(n):
num_cube = {}
for i in range(1, n+1):
j = i**3
more_info = {i :j}
num_cube.update(more_info)
return num_cube

[chaitanyaubale]

def cubeteller(n):
Dict={}
for i in range(1, n+1):
Dict.update({i:i*i*i})
return Dict

[shaguntripathi]

Take a minute to thank Harshit for providing & teaching "premium" content for free❤️
Thank you for this❤️

[vishnujatav]

Good but not able to understand how cubes[I] is returning in the form of a dictionary.

[harikadas]

def cubedict(n):
retdict = {}
for i in range(1, n+1):
temptup = {i : i**3}
retdict.update(temptup)
return retdict

print(cubedict(50))

[vishal]

bhai yeh error aa rha h UnboundLocalError: local variable 'i' referenced before assignment

[teach-with-noor]

num = int(input("Enter number"))
cube = {}
def cubes(a):
for b in range(1, 1+a):
cube[b] = b*b*b
return cube
print(cubes(num))

[pratikchaudhari]

n=int(input("enter the number "))
def cube_finder(l):

cube_f={}
cube={}
i=1
while i<l or i==l:
cube[i]=i**3
cube_f.update(cube)
i=i+1
return cube_f
print(cube_finder(n))

[CmonRishi]

why every time it seems so easy, when you do it ;)